shift. Shifts all the values of an array on its left. unshift. Adds the list element to the front of an array.
shift uses the @_ variable which contains the values passed to a function or shift uses @ARGV for the values passed to the script itself if shift is referenced outside of a function.
9.3. The Binding Operator, =~ Matching against $_ is merely the default; the binding operator (=~) tells Perl to match the pattern on the right against the string on the left, instead of matching against $_.
Perl | push() Functionpush() function in Perl is used to push a list of values onto the end of the array. push() function is often used with pop to implement stacks. push() function doesn't depend on the type of values passed as list.
shift()
is a built in Perl subroutine that takes an array as an argument, then returns and deletes the first item in that array. It is common practice to obtain all parameters passed into a subroutine with shift
calls. For example, say you have a subroutine foo
that takes three arguments. One way to get these parameters assigned to local variables is with shift
like so:
sub foo() {
my $x = shift;
my $y = shift;
my $z = shift;
# do something
}
The confusion here is that it appears shift is not being passed an array as an argument. In fact, it is being passed the "default" array implicitly, which is @_
inside a subroutine or @ARGV
outside a subroutine.
The shift
function removes the first element from an array, and returns it. The array is shortened by one element.
The default array (if one isn't given as a parameter) is @_
if you're in a function, or @ARGV
if you're at file scope.
So in this case $x
is either being set to the first function parameter, or to the first command line parameter.
In Perl, many methods use the default variables ($_
and @_
) if you don't explicitly specify arguments. Your code is identical to:
my $x = shift @_;
As pointed out by PullMonkey earlier, within a subroutine, @_
contains the arguments passed to that subroutine (as described in perlsub
). shift
will remove the first argument value from @_
and store it in $x
, so $_[0]
will now give you the second argument passed to your subroutine.
This is usually an idiom for: $x is a local variable assigned to the first parameter passed to the subroutine, although.
my ($x) = @_;
is probably clearer (and it doesn't modify the argument list).
In layman's terms, from a very highlevel view, shift is taking the first element of an array (the leftmost part), while the opposite is pop which is taking the last element of array (the rightmost part).
my @array1=(5,6,7,8,9); my $x = shift @array1; print "$x\n"; # 5 print "@array1\n"; # 6 7 8 9
If you are in a subroutine this line will shift
on @_
(the params that are passed in).
So $x
would be the first item popped
from the @_
array.
So usually you would see $x = shift if @_;
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