what does L represent in "<any hex number>L"

Question

I am looking through some c++ code and I came across this:

if( (size & 0x03L) != 0 )
    throw MalformedBundleException( "bundle size must be multiple of four" );

what does L stand for after the hexadecimal value ?

how does it alter the value 0x03 ?

Answer 1

It means Long, as in, the type of the literal 0x03L is long instead of the default int. On some platforms that will mean 64 bits instead of 32 bits, but that's entirely platform-dependent (the only guarantee is that long is not shorter than int).