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In the following regex what does "(?i)" and "?@" mean?
(?i)<.*?@(?P<domain>\w+\.\w+)(?=>) I know that "?" means zero or one and that i sets case insensitivity.
This regex captures domains from an email address in a mailto field, but does not include the @ sign. It was generated the erex command from within SPLUNK 6.0.2
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Following example shows how to search duplicate words in a regular expression by using p. matcher() method and m. group() method of regex. Matcher class.
2. What is the significance of $ used in regular expression in UNIX? Explanation: Regular expression provides more flexibility while matching string patterns.
3.6. (? i) makes the regex case insensitive. (? s) for "single line mode" makes the dot match all characters, including line breaks.
Basically (0+1)* mathes any sequence of ones and zeroes. So, in your example (0+1)*1(0+1)* should match any sequence that has 1. It would not match 000 , but it would match 010 , 1 , 111 etc. (0+1) means 0 OR 1.
demo here : https://regex101.com/r/hE9gB4/1
(?i)<.*?@(?P<domain>\w+\.\w+)(?=>) its actually getting your domain name from the email id:
(?i) makes it match case insensitive and
?@ is nothing but @ which matches the character @ literally.
the ? in your ?@ is part of .*? which we call as a lazy operator, It will give you the text between the < and @
if you dont use the ? after the .* it will match everything after < to the end. ( we call this as the greedy operator)
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? here is the UNGREEDY or LAZYNESS modifier:
.*?
It means: "everything is good until the @ character that follows is detected". Otherwise .* would match everything until the end of the string.
Read about it here: http://www.regular-expressions.info/repeat.html
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