Reuse part of a Regex pattern

Question

No, when using the standard library re module, regular expression patterns cannot be 'symbolized'.

You can always do so by re-using Python variables, of course:

digit_letter_letter_digit = r'\d\w\w\d'

then use string formatting to build the larger pattern:

match(r"{0},{0}".format(digit_letter_letter_digit), inputtext)

or, using Python 3.6+ f-strings:

dlld = r'\d\w\w\d'
match(fr"{dlld},{dlld}", inputtext)

I often do use this technique to compose larger, more complex patterns from re-usable sub-patterns.

If you are prepared to install an external library, then the regex project can solve this problem with a regex subroutine call. The syntax (?<digit>) re-uses the pattern of an already used (implicitly numbered) capturing group:

(\d\w\w\d),(?1)
^........^ ^..^
|           \
|             re-use pattern of capturing group 1  
\
  capturing group 1

You can do the same with named capturing groups, where (?<groupname>...) is the named group groupname, and (?&groupname), (?P&groupname) or (?P>groupname) re-use the pattern matched by groupname (the latter two forms are alternatives for compatibility with other engines).

And finally, regex supports the (?(DEFINE)...) block to 'define' subroutine patterns without them actually matching anything at that stage. You can put multiple (..) and (?<name>...) capturing groups in that construct to then later refer to them in the actual pattern:

(?(DEFINE)(?<dlld>\d\w\w\d))(?&dlld),(?&dlld)
          ^...............^ ^......^ ^......^
          |                    \       /          
 creates 'dlld' pattern      uses 'dlld' pattern twice

Just to be explicit: the standard library re module does not support subroutine patterns.

Note: this will work with PyPi regex module, not with re module.

You could use the notation (?group-number), in your case:

(\d\w\w\d),(?1)

it is equivalent to:

(\d\w\w\d),(\d\w\w\d)

Be aware that \w includes \d. The regex will be:

(\d[a-zA-Z]{2}\d),(?1)