What does for row_number, row in enumerate(cursor):
do in Python?
What does enumerate
mean in this context?
The enumerate function in Python converts a data collection object into an enumerate object. Enumerate returns an object that contains a counter as a key for each value within an object, making items within the collection easier to access.
To enumerate is defined as to mention things one by one or to make clear the number of things. An example of enumerate is when you list all of an author's works one by one. verb.
In computer programming, an enumerated type (also called enumeration, enum, or factor in the R programming language, and a categorical variable in statistics) is a data type consisting of a set of named values called elements, members, enumeral, or enumerators of the type.
Enumerate() in Python Enumerate() method adds a counter to an iterable and returns it in a form of enumerating object. This enumerated object can then be used directly for loops or converted into a list of tuples using the list() method.
The enumerate()
function adds a counter to an iterable.
So for each element in cursor
, a tuple is produced with (counter, element)
; the for
loop binds that to row_number
and row
, respectively.
Demo:
>>> elements = ('foo', 'bar', 'baz')
>>> for elem in elements:
... print elem
...
foo
bar
baz
>>> for count, elem in enumerate(elements):
... print count, elem
...
0 foo
1 bar
2 baz
By default, enumerate()
starts counting at 0
but if you give it a second integer argument, it'll start from that number instead:
>>> for count, elem in enumerate(elements, 42):
... print count, elem
...
42 foo
43 bar
44 baz
If you were to re-implement enumerate()
in Python, here are two ways of achieving that; one using itertools.count()
to do the counting, the other manually counting in a generator function:
from itertools import count
def enumerate(it, start=0):
# return an iterator that adds a counter to each element of it
return zip(count(start), it)
and
def enumerate(it, start=0):
count = start
for elem in it:
yield (count, elem)
count += 1
The actual implementation in C is closer to the latter, with optimisations to reuse a single tuple object for the common for i, ...
unpacking case and using a standard C integer value for the counter until the counter becomes too large to avoid using a Python integer object (which is unbounded).
It's a builtin function that returns an object that can be iterated over. See the documentation.
In short, it loops over the elements of an iterable (like a list), as well as an index number, combined in a tuple:
for item in enumerate(["a", "b", "c"]):
print item
prints
(0, "a")
(1, "b")
(2, "c")
It's helpful if you want to loop over a sequence (or other iterable thing), and also want to have an index counter available. If you want the counter to start from some other value (usually 1), you can give that as second argument to enumerate
.
I am reading a book (Effective Python) by Brett Slatkin and he shows another way to iterate over a list and also know the index of the current item in the list but he suggests that it is better not to use it and to use enumerate
instead.
I know you asked what enumerate means, but when I understood the following, I also understood how enumerate
makes iterating over a list while knowing the index of the current item easier (and more readable).
list_of_letters = ['a', 'b', 'c']
for i in range(len(list_of_letters)):
letter = list_of_letters[i]
print (i, letter)
The output is:
0 a
1 b
2 c
I also used to do something, even sillier before I read about the enumerate
function.
i = 0
for n in list_of_letters:
print (i, n)
i += 1
It produces the same output.
But with enumerate
I just have to write:
list_of_letters = ['a', 'b', 'c']
for i, letter in enumerate(list_of_letters):
print (i, letter)
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