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a = [1,2,3,4,5] b = [1,3,5,6] c = a and b print c actual output: [1,3,5,6] expected output: [1,3,5]
How can we achieve a boolean AND operation (list intersection) on two lists?
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Intersection of two list means we need to take all those elements which are common to both of the initial lists and store them into another list.
Intersection of Two Lists of StringsList<String> list = Arrays. asList("red", "blue", "blue", "green", "red"); List<String> otherList = Arrays. asList("red", "green", "green", "yellow");
Step1: input the elements of three lists. Step2: Use intersection method, first convert lists to sets then apply intersection method of two sets and find out common elements then this set intersect with the third set.
Python count intersection of sets To count the intersection of sets in Python, we will use “len(set(set1) & set(set2))”. Here, ” & “ is an intersection element common to both. It will return the count as “3” because “10, 8, and 6” are common to both the sets.
If order is not important and you don't need to worry about duplicates then you can use set intersection:
>>> a = [1,2,3,4,5] >>> b = [1,3,5,6] >>> list(set(a) & set(b)) [1, 3, 5] Using list comprehensions is a pretty obvious one for me. Not sure about performance, but at least things stay lists.
[x for x in a if x in b]
Or "all the x values that are in A, if the X value is in B".
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