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I hope this question is not too stupid... I have no idea what the ^ operator does in Go, e.g.
a := 3^500
At first I thought it must be pow but it most certainly is not. It's not mod (%) either.
I've tried looking through the doc and searching on Google, but unfortunately Google doesn't think ^ is a search term.
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A Hands-On Approach DOs use osteopathic manipulative treatment (OMT) to help identify and correct the source of the underlying health concerns. They use this technique to help treat low back pain, as well as a variety of other health problems, including headaches and sinus issues.
Heart and Vascular Care is excited to welcome the newest physician to our medical team, Stephen Fedec, DO, FACC, a board-certified interventional cardiologist. He explains, “A D.O. is an osteopathic physician, while an M.D. is a medical doctor, an allopathic physician.”
In general, an MD and a DO fulfill the same roles. An MD and a DO complete similar residencies, prescribe medications, and can practice in all 50 states. The main difference in DO versus MD is that DOs complete additional hands on training in a technique termed osteopathic manipulative medicine (OMM).
stand for “Doctor of Osteopathic Medicine.” A D.O. is granted to physicians who graduate from an osteopathic medical school. Osteopathic medicine is an approach to the practice of medicine that focuses on the unity of all body systems.
As in most languages, the caret operator is a bitwise XOR. You use it on integers.
Relevant Golang documentation
Wikipedia on the bitwise xor :
A bitwise XOR takes two bit patterns of equal length and performs the logical exclusive OR operation on each pair of corresponding bits. The result in each position is 1 if only the first bit is 1 or only the second bit is 1, but will be 0 if both are 0 or both are 1. In this we perform the comparison of two bits, being 1 if the two bits are different, and 0 if they are the same
The bitwise XOR may be used to invert selected bits in a register (also called toggle or flip). Any bit may be toggled by XORing it with 1. For example, given the bit pattern 0010 (decimal 2) the second and fourth bits may be toggled by a bitwise XOR with a bit pattern containing 1 in the second and fourth positions:
0010 (decimal 2)
XOR 1010 (decimal 10)
= 1000 (decimal 8)
This technique may be used to manipulate bit patterns representing sets of Boolean states.
Adding the comment from @karmakaze to this answer for more helpful info:
Also as a unary operator, it's bitwise not. e.g.
^uint(0)results in theuintvalue0xfffffffffor 32-bit machine and longer for a 64-bit machine.
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