Java lambda returning a lambda

Question

I am trying to do what seems to be a relatively basic thing in the new JDK 8 land of functional programming, but I can't get it to work. I have this working code:

import java.util.*; import java.util.concurrent.*; import java.util.stream.*;  public class so1 {    public static void main() {       List<Number> l = new ArrayList<>(Arrays.asList(1, 2, 3));       List<Callable<Object>> checks = l.stream().                map(n -> (Callable<Object>) () -> {                   System.out.println(n);                   return null;                }).                collect(Collectors.toList());    } } 

It takes a list of numbers and produces a list of functions that can print them out. However, the explicit cast to Callable seems redundant. It seems to me and to IntelliJ. And we both agree that this should also work:

List<Callable<Object>> checks = l.stream().        map(n -> () -> {           System.out.println(n);           return null;        }).        collect(Collectors.toList()); 

However I get an error:

so1.java:10: error: incompatible types: cannot infer type-variable(s) R       List<Callable<Object>> checks = l.stream().map(n -> () -> {System.out.println(n); return null;}).collect(Collectors.toList());                                                     ^     (argument mismatch; bad return type in lambda expression       Object is not a functional interface)   where R,T are type-variables:     R extends Object declared in method <R>map(Function<? super T,? extends R>)     T extends Object declared in interface Stream 1 error 

Answer 1

You hit a limitation of Java 8’s target typing which applies to the receiver of a method invocation. While target typing works (most of the times) for parameter types it does not work for the object or expression on which you invoke the method.

Here, l.stream(). map(n -> () -> { System.out.println(n); return null; }) is the receiver of the collect(Collectors.toList()) method invocation, so the target type List<Callable<Object>> is not considered for it.

It’s easy to prove that nested lambda expressions work if the target type is know, e.g.

static <T> Function<T,Callable<Object>> toCallable() {     return n -> () -> {         System.out.println(n);          return null;     }; } 

works without problems and you can use it to solve your original problem as

List<Callable<Object>> checks = l.stream()     .map(toCallable()).collect(Collectors.toList()); 

You can also solve the problem by introducing a helper method which changes the role of the first expression from method receiver to a parameter

// turns the Stream s from receiver to a parameter static <T, R, A> R collect(Stream<T> s, Collector<? super T, A, R> collector) {     return s.collect(collector); } 

and rewrite the original expression as

List<Callable<Object>> checks = collect(l.stream().map(     n -> () -> {         System.out.println(n);          return null;     }), Collectors.toList()); 

This does not reduce the complexity of the code but can be compiled without any problems. For me, it’s a déjà vu. When Java 5 and Generics came out, programmers had to repeat the type parameters on new expressions while simply wrapping the expression into a generic method proved that inferring the type is no problem. It took until Java 7 before programmers were allowed to omit these unnecessary repetition of the type arguments (using the “diamond operator”). Now we have a similar situation, wrapping an invocation expression into another method, turning the receiver into a parameter, proves that this limitation is unnecessary. So maybe we get rid of this limitation in Java 10…

Answer 2

I ran into this same issue and was able to solve it by explicitly specifying the generic type-parameter to map like so:

List<Callable<Object>> checks = l.stream().    <Callable<Object>>map(n -> () -> {       System.out.println(n);        return null;    }).    collect(Collectors.toList());