Does ~0 mean its flipping 000000000 to 1111111111?
printf("Check: %i", ~0);
The printf results to -1, which is why I am confused.
Does -1 essentially mean the same thing as 11111111111111111 bits?
Does ~0 mean its flipping 000000000 to 1111111111?
Yes, it does.
Does -1 essentially mean the same thing as 11111111111111111 bits?
In 2s complement representation, it does.
Does ~0 mean its flipping 000000000 to 1111111111?
Yes, that's what it means.
printf("Check: %i", ~0);
The printf results to -1, which is why I am confused.
That's because of 2's complement arithmetic, where we have conventionally accepted zero to be
000000000000
and subtracting one from it requires a "borrow" that requires a borrow, and so on, until you "roll" the entire register
111111111111
Logically, if you add "1" to that number, it will carry, and carry, and so on until it "rolls" in the opposite direction, yielding 000000000
again.
Does -1 essentially mean the same thing as 11111111111111111 bits?
Yes, as long as you are using 2's complement signed integers.
---- Edited, to include details from cincutar's now deleted post (I wish he didn't delete it) ---
To see the same memory formatted as a (unsigned) hexadecimal number, use the command
printf("Check: %x", ~0);
which will print the output
Check ffffffff
which is (for those who don't read hexadecimal well)
11111111111111111111111111111111
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