I am getting the above warning when I try to run this code:
$mysqli=new mysqli("localhost", "***", "***","***") or die(mysql_error());
function checklogin($username, $password){
global $mysqli;
$result = $mysqli->prepare("SELECT * FROM users WHERE username = ?");
$result->bind_param("s", $username);
$result->execute();
if($result != false){
$dbArray=mysql_fetch_array($result);
You are mixing mysqli
and traditional mysql
commands.
Use $result->fetch_array()
.
You are mixing mysql and mysqli calls in your code. Use mysqli_fetch_array
instead of mysql_fetch_array
.
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