I get the following error
Warning: mysqli_error() expects exactly 1 parameter, 0 given
The problem is with this line of the code:
$query = mysqli_query($myConnection, $sqlCommand) or die (mysqli_error());
The whole code is
session_start(); require_once "scripts/connect_to_mysql2.php"; //Build Main Navigation menu and gather page data here $sqlCommand = "SELECT id, linklabel FROM pages ORDER BY pageorder ASC"; $query = mysqli_query($myConnection, $sqlCommand) or die (mysqli_error()); $menuDisplay = ''; while ($row = mysqli_fetch_array($query)) { $pid = $row["id"]; $linklabel = $row["linklabel"]; $menuDisplay .= '<a href="index.php?pid=' . $pid . '">' . $linklabel . '</a><br />'; } mysqli_free_result($query);
The included file has the following line
$myConnection = mysqli_connect("$db_host","$db_username","$db_pass","$db_name") or die ("could not connect to mysql"); with reference to $myConnection, why do I get this error?
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