As we know, we can use vue-route
to wrap some route paths.
<!-- vue 1.x -->
<a v-link="{name: 'route_name', params: {id: 1}}"></a>
And in vue2:
<!-- vue 2.x -->
<router-link :to="{name: 'route_name', params: {id: 1}}"></router-link>
And now, I want to display a link url for the user to copy, so I wonder if there is a way to return the absolute path url from a route object? It seemed the docs did not mention that.
For example, I want:
<template>
<label>Copy the address</label>
<input value="url" />
</template>
<script>
export default {
computed: {
url() {
const route = {name: 'route_name', params: {id: 1}};
// !! The bellow shows what I may want.
return this.$router.getLink(route);
},
}.
};
</script>
Is there such a method?
For future people looking to do this
I believe this is the Vue 2.x way
var path = this.$router.resolve({name: 'SomePath', params: {id: 1}}).href
then if you want the full url you would do
var fullUrl = window.location.origin + "/" + path
In Vue 2.0 maybe you can try my way: this.$route.path
can get the URL path without domain. For example: http://localhost:8000/#/reg
only gets the /reg
part; the domain part you can get it easily outside the VueRouter. BTW: after creating const router = new VueRouter ...
, you can get the URL by using router.history.current.path;
. This method can get the URL like /reg
too.
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