visual studio code PHP debugging not working

Question

I have installed VS Code and the PHP debugger.

I am using xampp.

I tried running the code (2) ways (listen and launch).

Listen just sits there while Launch shows spawn php ENOENT in the debug console.

This is my launch.json.

    {     "version": "0.2.0",     "configurations": [          {             "name": "Listen for XDebug",             "type": "php",             "request": "launch",             "port": 9000         },         {             "name": "Launch currently open script",             "type": "php",             "request": "launch",             "program": "${file}",             "cwd": "${fileDirname}",             "port": 9000         }     ] } 

What am I doing wrong?

Answer 1

Made it just now:

1. We have OS Windows with Microsoft Visual Code and we have installed 'PHP Debug' module https://marketplace.visualstudio.com/items?itemName=felixfbecker.php-debug#overview Steps to make it working already wroten here, but I'll write again:
   

2. Install XDebug. Online Wizard https://xdebug.org/wizard.php helps you, just post here phpinfo() data. Save in phpinfo.php this:
   

   <?php phpinfo(); ?> 

then open in browser localhost/phpinfo.php, copy everything you see (Ctrl+A then Ctrl+C) to wizard. It shows you obtained info and steps to do:

2. Open shown in instruction php.ini (there are always many php.ini - apache folder has one php.ini, php has php.ini and phpForApache.ini. But phpinfo makes it clear showing which one is really used)

   2.1. and configure it with xdebug.remote_enable = 1 and xdebug.remote_autostart = 1. My working example:

   [XDebug] zend_extension = "c:\wamp64\bin\php\php7.1.9\ext\php_xdebug-2.6.0beta1-7.1-vc14-x86_64.dll"     xdebug.stopOnEntry = true xdebug.profiler_enable = off xdebug.profiler_enable_trigger = Off xdebug.profiler_output_name = cachegrind.out.%t.%p xdebug.profiler_output_dir ="c:/wamp64/tmp" xdebug.show_local_vars=0 ;xdebug.profiler_output_name = "cachegrind.out.%t-%s" xdebug.remote_enable = 1 xdebug.remote_autostart = 1 xdebug.remote_handler = "dbgp" xdebug.remote_host = "127.0.0.1" xdebug.remote_log = "C:\wamp64\tmp\xdebug.txt" xdebug.remote_port = 9000 xdebug.trace_output_dir = "C:\wamp64\tmp" xdebug.remote_cookie_expire_time = 36000 

3. Restart Apache2 webserver.
   

Also:

For some reason I first got xdebug working on Netbeans for testing, and only then I found option xdebug.remote_autostart = 1 in manual that made it working in VS Code also.

If you are unsure about XDebug installation, check phpinfo page for "with Xdebug" words and check logs/apache_errors.log for "failed loading php_xdebug" (incorrect DDL downloaded). Then check with any other IDE.

Good regards!

Answer 2

For anyone looking answer today, for me helped changing in php.ini section [XDebug] to this:

xdebug.mode = debug xdebug.start_with_request = yes zend_extension = "C:\xampp\php\ext\php_xdebug.dll" xdebug.stopOnEntry = true xdebug.profiler_enable = off xdebug.profiler_enable_trigger = Off xdebug.profiler_output_name = cachegrind.out.%t.%p xdebug.output_dir ="c:\xampp\tmp" xdebug.show_local_vars=0 xdebug.remote_handler = "dbgp" xdebug.client_host = "127.0.0.1" xdebug.log = "C:\xampp\tmp\xdebug.txt" xdebug.client_port = 9000 xdebug.remote_cookie_expire_time = 36000 

I used the settings from post of @Eluny, but with some newer version of the XDebug the properties names changed. On documentation page you can find info about changes