Vim: How do I search for a word which is not followed by another word?

Question

Pretty basic question, I'm trying to write a regex in Vim to match any phrase starting with "abc " directly followed by anything other than "defg".

I've used "[^defg]" to match any single character other than d, e, f or g.

My first instinct was to try /abc [^\(defg\)] or /abc [^\<defg\>] but neither one of those works.

Answer 1

Here's the search string.

/abc \(defg\)\@! 

The concept you're looking for is called a negative look-ahead assertion. Try this in vim for more info:

:help \@! 

Answer 2

preceeded or followed by?

If it's anything starting with 'abc ' that's not (immediately) followed by 'defg', you want bmdhacks' solution.

If it's anything starting with 'abc ' that's not (immediately) preceeded by 'defg', you want a negative lookbehind:

/\%(defg\)\@<!abc / 

This will match any occurance of 'abc ' as long as it's not part of 'defgabc '. See :help \@<! for more details.

If you want to match 'abc ' as long as it's not part of 'defg.*abc ', then just add a .*:

/\%(defg.*\)\@<!abc / 

Matching 'abc ' only on lines where 'defg' doesn't occur is similar:

/\%(defg.*\)\@<!abc \%(.*defg\)\@!/ 

Although, if you're just doing this for a substitution, you can make this easier by combining :v// and :s//

:%v/defg/s/abc /<whatever>/g 

This will substitute '<whatever>' for 'abc ' on all lines that don't contain 'defg'. See :help :v for more.