I am trying to substract 2 std logic vector and get error
p2 <= p1(11 downto 0)- idata(11 downto 0);
Error (10327): VHDL error at sub.vhd(32): can't determine definition of operator ""-"" -- found 0 possible definitions
I already tried to add use IEEE.std_logic_signed.all
or use IEEE.std_logic_unsigned.all
or both and already tried
p2 <= std_logic_vector(unsigned(p1(11 downto 0)) - unsigned(idata(11 downto 0)));
library ieee;
use ieee.std_logic_1164.all;
use ieee.std_logic_arith.all;
--use IEEE.std_logic_signed.all;
--use IEEE.std_logic_unsigned.all;
entity sub is
port (
clk : in std_logic;
rst : in std_logic;
--en : in std_logic;
idata : in std_logic_vector (11 downto 0);
odata : out std_logic_vector (11 downto 0)
);
end sub;
architecture beh of sub is
signal p1,p2 :std_logic_vector (11 downto 0);
begin
process (clk, rst)
begin
if (rst = '1') then
odata <= "000000000000";
elsif (rising_edge (clk)) then
p1 <= idata;
p2 <= p1(11 downto 0)- idata(11 downto 0);
--p2 <= std_logic_vector(unsigned(p1(11 downto 0)) - unsigned(idata(11 downto 0)));
end if;
end process;
odata<=p2;
end beh;
The std_logic_vector
type is just an array of std_logic
, and does not by itself have any numerical interpretation, thus the error when trying to apply numeric operations like minus (-
).
Don't use the Synopsys non-standard std_logic_signed/unsigned/arith
packages.
VHDL-2002: use the unsigned
type in the standard ieee.numeric_std
package to convert a std_logic_vector
to a unsigned
representation, which allows use of numeric operations like minus. Code like:
use ieee.numeric_std.all;
...
p2 <= std_logic_vector(unsigned(p1(11 downto 0)) - unsigned(idata(11 downto 0)));
VHDL-2008: use the standard ieee.numeric_std_unsigned
package to convert a std_logic_vector
to a unsigned
representation, which allows use of numeric operations like minus. Code like:
use ieee.numeric_std_unsigned.all;
...
p2 <= p1(11 downto 0) - idata(11 downto 0);
Btw. check out this search for similar issues.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With