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Variadic sequence of pointer to recursive member of struct/class as template parameter

I'm struggling with some template programming and I hope you can give me some help. I coded a C++11 interface that, given some structs like:

struct Inner{
  double a;
};
struct Outer{
  double x, y, z, r;
  Inner in;
};

Implements a getter/setter to the real data that is customized to the specified struct members:

MyData<Outer, double, &Outer::x,
                               &Outer::y, 
                               &Outer::z,
                               &Outer::in::a //This one is not working
              > state();

Outer foo = state.get();
//...  
state.set(foo);

I managed to implement this for simple structs in the following way:

template <typename T, typename U, U T::* ... Ms>
class MyData{
   std::vector<U *> var;
  public:
    explicit MyData();
    void set(T const& var_);
    T get() const;
};

template <typename T, typename U, U T::* ... Ms>
MyData<T, U, Ms ... >::Struct():var(sizeof...(Ms))
{
}

template <typename T, typename U, U T::* ... Ms>
void MyData<T, U, Ms ...>::set(T const& var_){
  unsigned i = 0;
  for ( auto&& d : {Ms ...} ){
    *var[i++] = var_.*d;
  }
}

template <typename T, typename U, U T::* ... Ms>
T MyData<T, U, Ms ...>::get() const{
  T var_;
  unsigned i = 0;
  for ( auto&& d : {Ms ...} ){
    var_.*d = *var[i++];
  }
  return var_;
}

But it fails when I pass a member of a nested struct. Ideally, I'd like to implement a generic pointer to member type that allows me to be compatible with several levels of scope resolutions. I found this approach, but I'm not sure if this should be applied to my problem or if there exists some implementation ready to use. Thanks in advance!

Related posts:

Implicit template parameters

Pointer to inner struct

like image 777
Manuel Castillo-Lopez Avatar asked Feb 04 '23 20:02

Manuel Castillo-Lopez


1 Answers

You might wrap member pointer into struct to allow easier chaining:

template <typename...> struct Accessor;

template <typename T, typename C, T (C::*m)>
struct Accessor<std::integral_constant<T (C::*), m>>
{
    const T& get(const C& c) { return c.*m; }
    T& get(C& c) { return c.*m; }
};

template <typename T, typename C, T (C::*m), typename ...Ts>
struct Accessor<std::integral_constant<T (C::*), m>, Ts...>
{
    auto get(const C& c) -> decltype(Accessor<Ts...>().get(c.*m))
    { return Accessor<Ts...>().get(c.*m); }

    auto get(C& c) -> decltype(Accessor<Ts...>().get(c.*m))
    { return Accessor<Ts...>().get(c.*m); }
};

template <typename T, typename U, typename ...Ts>
class MyData
{
    std::vector<U> vars{sizeof...(Ts)};

    template <std::size_t ... Is>
    T get(std::index_sequence<Is...>) const
    {
        T res;
        ((Ts{}.get(res) = vars[Is]), ...); // Fold expression C++17
        return res;
    }
    template <std::size_t ... Is>
    void set(std::index_sequence<Is...>, T const& t)
    {
        ((vars[Is] = Ts{}.get(t)), ...); // Fold expression C++17
    }

public:
    MyData() = default;

    T get() const { return get(std::index_sequence_for<Ts...>()); }
    void set(const T& t) { return set(std::index_sequence_for<Ts...>(), t); }

};

With usage similar to

template <auto ...ms> // C++17 too
using Member = Accessor<std::integral_constant<decltype(ms), ms>...>;

MyData<Outer, double, Member<&Outer::x>,
                           Member<&Outer::y>,
                           Member<&Outer::z>,
                           Member<&Outer::in, &Inner::a>
       > state;

std::index_sequence is C++14 but can be implemented in C++11.
Folding expression from C++17 can be simulated too in C++11.
typename <auto> (C++17) should be replaced by typename <typename T, T value>.

Demo

like image 89
Jarod42 Avatar answered Feb 06 '23 12:02

Jarod42