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Variable in for loop undefined outside

Tags:

scope

go

I am wondering why the following piece of code is not working:

package main

import (
    "fmt"
)

func main() {
    for i := 0; i < 10000; i++ {
        var randomString = fmt.Sprintf("a%sa\n", "test")
    }
    fmt.Printf("Made 10000 random strings like", randomString);
}

I've stripped some unrelevant code (as this is obviously not really random).

The issue i'm having is that just under the for-loop, "randomString" is undefined.

I've tried setting it using randomString := fmt.Sprintf() and with the var you've seen above.

I'm quite sure this is a scoping issue (the randomString variable is not in the scope outside of the for-loop), but as a PHP / JS developer, i'm not used to this and would say that variable is also available after the for loop.

How can I access that variable from that point? Basically just displaying the last generated string.

like image 756
Rob Avatar asked Nov 20 '15 09:11

Rob


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2 Answers

See the relevant section from the spec: Declarations and scope:

The scope of a constant or variable identifier declared inside a function begins at the end of the ConstSpec or VarSpec (ShortVarDecl for short variable declarations) and ends at the end of the innermost containing block.

Define it in the scope in which you want to access it: before the for (in the scope of the main() function).

Also note that fmt.Sprintf() requires an additional parameter besides the ones to be printed: a format string. Either provide a format string (e.g. include a %s verb for the randomString parameter) or alternatively you may use fmt.Sprintln().

func main() {
    var randomString string
    for i := 0; i < 10000; i++ {
        randomString = fmt.Sprintf("a%sa\n", "test")
    }
    fmt.Println("Made 10000 random strings like", randomString)
}

Output:

Made 10000 random strings like atesta

Try it on the Go Playground.

like image 181
icza Avatar answered Dec 18 '22 02:12

icza


This is scoping issue, in Go the scope of randomString is the loop body, in JS it would be the whole function. Scoping rules differ in the different languages.

Check the Go spec:

https://golang.org/ref/spec#Declarations_and_scope

like image 27
chill Avatar answered Dec 18 '22 01:12

chill