Validate URL with or without protocol

Question

Hi I would like to validate this following urls, so they all would pass with or without http/www part in them as long as there is TLD present like .com, .net, .org etc..

Valid URLs Should Be:

http://www.domain.com
http://domain.com
https://www.domain.com
https://domain.com
www.domain.com
domain.com

To support long tlds:

http://www.domain.com.uk
http://domain.com.uk
https://www.domain.com.uk
https://domain.com.uk
www.domain.com.uk
domain.com.uk

To support dashes (-):

http://www.domain-here.com
http://domain-here.com
https://www.domain-here.com
https://domain-here.com
www.domain-here.com
domain-here.com

Also to support numbers in domains:

http://www.domain1-test-here.com
http://domain1-test-here.com
https://www.domain1-test-here.com
https://domain1-test-here.com
www.domain1-test-here.com
domain-here.com

Also maybe allow even IPs:

127.127.127.127

(but this is extra!)

Also allow dashes (-), forgot to mantion that =)

I've found many functions that validate one or another but not both at same time. If any one knows good regex for it, please share. Thank you for your help.

Answer 1

For url validation perfect solution.

Above Answer is right but not work on all domains like .me, .it, .in

so please user below for url match:

$pattern = '/(?:https?:\/\/)?(?:[a-zA-Z0-9.-]+?\.(?:[a-zA-Z])|\d+\.\d+\.\d+\.\d+)/';

if(preg_match($pattern, "http://website.in"))
{
echo "valid";
}else{
echo "invalid";
}

Answer 2

When you ignore the path part and look for the domain part only, a simple rule would be

(?:https?://)?(?:[a-zA-Z0-9.-]+?\.(?:com|net|org|gov|edu|mil)|\d+\.\d+\.\d+\.\d+)

If you want to support country TLDs as well you must either supply a complete (current) list or append |.. to the TLD part.

With preg_match you must wrap it between some delimiters

$pattern = ';(?:https?://)?(?:[a-zA-Z0-9.-]+?\.(?:com|net|org|gov|edu|mil)|\d+\.\d+\.\d+\.\d+);';
$index = preg_match($pattern, $url);

Usually, you use /. But in this case, slashes are part of the pattern, so I have chosen some other delimiter. Otherwise I must escape the slashes with \

$pattern = '/(?:https?:\/\/)?(?:[a-zA-Z0-9.-]+?\.(?:com|net|org|gov|edu|mil)|\d+\.\d+\.\d+\.\d+)/';