Validate Mobile number using regular expression

Question

I need to validate mobile number. My need:

1. The number may start with +8801 or 8801 or 01
2. The next number can be 1 or 5 or 6 or 7 or 8 or 9
3. Then there have exact 8 digit.

How can i write the regular expression using this conditions ?

the mobile numbers I tried

+8801811419556
01811419556
8801711419556
01611419556
8801511419556

Answer 1

Should be pretty simple:

^(?:\+?88)?01[15-9]\d{8}$

• ^ - From start of the string
• (?:\+?88)? - optional 88, which may begin in +
• 01 - mandatory 01
• [15-9] - "1 or 5 or 6 or 7 or 8 or 9"
• \d{8} - 8 digits
• $ - end of the string

Working example: http://rubular.com/r/BvnSXDOYF8

Update 2020

As BTRC approved 2 new prefixes, 013 for Grameenphone and 014 for Banglalink, updated expression for now:

^(?:\+?88)?01[13-9]\d{8}$

Answer 2

You may use either one of given regular expression to validate Bangladeshi mobile number.

Solution 1:

/(^(\+88|0088)?(01){1}[56789]{1}(\d){8})$/

Robi, Grameen Phone, Banglalink, Airtel and Teletalk operator mobile no are allowed.

Solution 2:

 /(^(\+8801|8801|01|008801))[1|5-9]{1}(\d){8}$/

Citycell, Robi, Grameen Phone, Banglalink, Airtel and Teletalk operator mobile no are allowed.

Allowed mobile number pattern

+8801812598624

008801812598624

01812598624

01712598624

01919598624

01672598624

01512598624

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