Regex to match 10 or 12 digits only

Question

I tried to write a regex to match a 10 or 12 digits number combination. like:

1234567890 - True
123456789012 - True
12345678901 - False
123456- False

1234567890123- False

Only match either 10 or 12 digits. I tried this:

"^[0-9]{10}|[0-9]{12}$"

Answer 1

You're close!

This is the regex you're looking for: ^(\d{10}|\d{12})$. It checks for digits (with \d). The rest is more or less your code, with the exception of the parenthesis. It captures each group. You could loose those, if you want to work without it!

See it in action here

Answer 2

Your regex either matches 10 digits at the beginning of a string (with any characters more allowed after that), or 12 digits at the end of the string. One option to make your regex work is:

"^[0-9]{10}$|^[0-9]{12}$"

although it's better to use raw strings for the pattern:

r'^[0-9]{10}$|^[0-9]{12}$'