I have a small python project that has the following structure -
Project -- pkg01 -- test01.py -- pkg02 -- test02.py -- logging.conf
I plan to use the default logging module to print messages to stdout and a log file. To use the logging module, some initialization is required -
import logging.config logging.config.fileConfig('logging.conf') logger = logging.getLogger('pyApp') logger.info('testing')
At present, I perform this initialization in every module before I start logging messages. Is it possible to perform this initialization only once in one place such that the same settings are reused by logging all over the project?
if you transform the second module in a class, you can simply: declare the logger in the first modulue. create the new class passing the 2 logger as parameters. use the logger in the new class.
Python logger with multiple handlers (stream, file, etc.), so you can write log to multiple targets at once · GitHub.
The built-in python logger is I/O blocking. This means that using the built-in logging module will interfere with your asynchronous application performance. aiologger aims to be the standard Asynchronous non-blocking logging for python and asyncio.
Python comes with a logging module in the standard library that provides a flexible framework for emitting log messages from Python programs. This module is widely used by libraries and is the first go-to point for most developers when it comes to logging.
Best practice is, in each module, to have a logger defined like this:
import logging logger = logging.getLogger(__name__)
near the top of the module, and then in other code in the module do e.g.
logger.debug('My message with %s', 'variable data')
If you need to subdivide logging activity inside a module, use e.g.
loggerA = logging.getLogger(__name__ + '.A') loggerB = logging.getLogger(__name__ + '.B')
and log to loggerA
and loggerB
as appropriate.
In your main program or programs, do e.g.:
def main(): "your program code" if __name__ == '__main__': import logging.config logging.config.fileConfig('/path/to/logging.conf') main()
or
def main(): import logging.config logging.config.fileConfig('/path/to/logging.conf') # your program code if __name__ == '__main__': main()
See here for logging from multiple modules, and here for logging configuration for code which will be used as a library module by other code.
Update: When calling fileConfig()
, you may want to specify disable_existing_loggers=False
if you're using Python 2.6 or later (see the docs for more information). The default value is True
for backward compatibility, which causes all existing loggers to be disabled by fileConfig()
unless they or their ancestor are explicitly named in the configuration. With the value set to False
, existing loggers are left alone. If using Python 2.7/Python 3.2 or later, you may wish to consider the dictConfig()
API which is better than fileConfig()
as it gives more control over the configuration.
Actually every logger is a child of the parent's package logger (i.e. package.subpackage.module
inherits configuration from package.subpackage)
, so all you need to do is just to configure the root logger. This can be achieved by logging.config.fileConfig
(your own config for loggers) or logging.basicConfig
(sets the root logger). Setup logging in your entry module (__main__.py
or whatever you want to run, for example main_script.py
. __init__.py
works as well)
using basicConfig:
# package/__main__.py import logging import sys logging.basicConfig(stream=sys.stdout, level=logging.INFO)
using fileConfig:
# package/__main__.py import logging import logging.config logging.config.fileConfig('logging.conf')
and then create every logger using:
# package/submodule.py # or # package/subpackage/submodule.py import logging log = logging.getLogger(__name__) log.info("Hello logging!")
For more information see Advanced Logging Tutorial.
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