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Using Linq To XML, method to get path to all leaves?

Ok, I've got the following XML tree

<root>
    <A>
        <A1>
            <A1A>1000</A1A>
            <A1B>2000</A1B>
            <A1C>3000</A1C>
        </A1>
        <A2>
            <A2A>4000</A2A>
            <A2B>5000</A2B>
        </A2>
    </A>
    <B>
        <B1>
            <B1A>6000</B1A>
        </B1>
    </B>
</root>

From a method receiving an XDocument I want to produce a dictionary where the key is the path (really an XPath) and the value comes from the value in the corresponding leaf.

root/A/A1/A1A    1000
root/A/A1/A1B    2000
root/A/A1/A1C    3000
root/A/A2/A2A    4000
root/A/A2/A2B    5000
root/B/B1/B1A    6000

Seems simple to do in Linq to XML but I can't wrap my head around it.

like image 458
Stécy Avatar asked Jan 09 '12 21:01

Stécy


2 Answers

You can find the leaves by looking for elements that have no descendants:

var doc = XDocument.Load(fileName);
var leaves = 
    from e in doc.Descendants()
    where !e.Elements().Any()
    select e;

I don't know if there is a built-in way to get the path of an element, but you can easily create an extension method to build it:

static class Extensions
{
    public static string Path(this XElement element)
    {
        XElement tmp = element;
        string path = string.Empty;
        while (tmp != null)
        {
            path = "/" + tmp.Name + path;
            tmp = tmp.Parent;
        }
        return path;
    }
}

You can then build the dictionary like this:

var dict = leaves.ToDictionary(e => e.Path(), e => e.Value);
like image 97
Thomas Levesque Avatar answered Oct 09 '22 11:10

Thomas Levesque


After parsing the XML to an XDocument, which I assume you've already been able to do, use the methods below. Note that the GetPath() implementation is fairly naiive. See this answer for a better implementation.

public Dictionary<string, string> GetLeaves(XDocument doc)
{
    var dict = doc
        .Descendants()
        .Where(e => !e.HasElements)
        .ToDictionary(e => GetPath(e), e.Value);

    return dict;
}

private string GetPath(XElement element)
{
    var nodes = new List<string>();
    var node = element;
    while (node != null)
    {
        nodes.Add(node.Name.ToString());
        node = node.Parent;
    }

    return string.Join("/", Enumerable.Reverse(nodes));
}
like image 38
Phil Klein Avatar answered Oct 09 '22 12:10

Phil Klein