GCC
and Clang
do compile the following code:
void Test()
{
constexpr int Size = 3;
auto Lambda = [Size]{ int Dim[Size]; };
}
However, VisualStudio 2015 CTP 6
does not. Nevertheless, all 3 compilers are happy with this code:
void Test()
{
static constexpr int Size = 3;
auto Lambda = []{ int Dim[Size]; };
}
Which snippet is actually doing it in the correct way? What does the C++ standard say?
This question is related to Lambda capturing constexpr object
C++11 [expr.prim.lambda]/12
If a lambda-expression odr-uses this or a variable with automatic storage duration from its reaching scope, that entity shall be captured by the lambda-expression.
and /17
Every id-expression that is an odr-use of an entity captured by copy is transformed into an access to the corresponding unnamed data member of the closure type. [ Note: An id-expression that is not an odr-use refers to the original entity, never to a member of the closure type. [...] — end note ]
So we don't even need to capture Size
in the first example (where it is not static
), since reading from that variable is not an odr-use since it can appear in a constant expression and the lvalue-to-rvalue conversion is immediately applied to it, [basic.def.odr]/2
A variable whose name appears as a potentially-evaluated expression is odr-used unless it is an object that satisfies the requirements for appearing in a constant expression and the lvalue-to-rvalue conversion is immediately applied.
(It is not clear to me if the array bounds require an l-t-r conversion, though.)
The same applies when capturing Size
by reference, or when capturing Size
explicitly (by copy) but not odr-using it: the use of the id-expression Size
within the lambda accesses the constexpr
variable declared in Test
, not any captured member (for capture-by-copy: IFF the access does not constitute an odr-use).
C++14 [expr.prim.lamda]/12 adds some wording for polymorphic lambdas that is irrelevant here, and moves /17 to /18. The rules for odr-use are more complicated, but I'd argue it's not an odr-use for the same underlying reason (reading a compile-time constant).
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