Using gson to deserialize specific JSON field of an object

Question

I have the following JSON string:

{     "ms": "images,5160.1",     "turl": "http://ts1.mm.bing.net/th?id=I4693880201938488&pid=1.1",     "height": "178",     "width": "300",     "imgurl": "http://www.attackingsoccer.com/wp-content/uploads/2011/07/World-Cup-2012-Draw.jpg",     "offset": "0",     "t": "World Cup 2014 Qualification – Europe Draw World Cup 2012 Draw ...",     "w": "719",     "h": "427",     "ff": "jpeg",     "fs": "52",     "durl": "www.attackingsoccer.com/2011/07/world-cup-2012-qualification-europe...",     "surl": "http://www.attackingsoccer.com/2011/07/world-cup-2012-qualification-europe-draw/world-cup-2012-draw/",     "mid": "D9E91A0BA6F9E4C65C82452E2A5604BAC8744F1B",     "k": "6",     "ns": "API.images" } 

I need to store the value of imgurl in a separate string.

This is what I have till now, but this just gives me the whole JSON string instead of the specific imgurl field.

Gson gson = new Gson(); Data data = new Data(); data = gson.fromJson(toExtract, Data.class); System.out.println(data); 

toExtract is the JSON string. Here is my data class:

public class Data  {     public List<urlString> myurls; }  class urlString {     String imgurl; } 

Answer 1

When parsing such a simple structure, no need to have dedicated classes.

Solution 1 :

To get the imgurURL from your String with gson, you can do this :

JsonParser parser = new JsonParser(); JsonObject obj = parser.parse(toExtract).getAsJsonObject(); String imgurl = obj.get("imgurl").getAsString(); 

This uses a raw parsing into a JsonObject.

Solution 2 :

Alternatively, you could extract your whole data in a Properties instance using

 Properties data = gson.fromJson(toExtract, Properties.class); 

and read your URL with

String imgurl = data.getProperty("imgurl");