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Using array.array in Python ctypes

Tags:

python

ctypes

I have to interface a Python program with a C library. The particular function I need to call takes an array and returns a double. The following function has the same signature and is easier to understand than my own:

double sum(double * array, const int length) {
 double total = 0;
 int i;
 for (i=0; i<length; i++) {
     total += array[i];
 }
 return total;
}

My current solution is:

import ctypes
lib = ctypes.CDLL(library_name) 

l = 10
arr = tuple(range(l))

lib.sum.restype = ctypes.c_double
values = (ctypes.c_double * l)(*arr)
ret = lib.sum(values, l)

But I use the array module a lot in my code and it seemed to me that using them with the C code should be more straight forward as it is a typed array. So I tried to feed the C function directly with an array but it did not work. To make it work, I wrapped array like this:

class Array(array):

   @property
   def _as_parameter_(self):
      return (TYPES[self.typecode] * len(self))(*self)

where TYPES map the typecode from the array to ctypes types:

   TYPES = {'c': ctypes.c_char,
            'b': ctypes.c_byte,
            'B': ctypes.c_ubyte,
            '?': ctypes.c_bool,
            'h': ctypes.c_short,
            'H': ctypes.c_ushort,
            'i': ctypes.c_int,
            'I': ctypes.c_uint,
            'l': ctypes.c_long,
            'L': ctypes.c_ulong,
            'q': ctypes.c_longlong,
            'Q': ctypes.c_ulonglong,
            'f': ctypes.c_float,
            'd': ctypes.c_double}

Is there a way to replace _as_parameter_ by something that does not create another array?

Thanks

like image 870
Hernan Avatar asked Oct 07 '22 19:10

Hernan


1 Answers

use array.buffer_info() to get the address and length, and cast() the address to POINTER(c_double):

from array import array
buf = array("d", range(101))
addr, count = buf.buffer_info()
print lib.sum(cast(addr, POINTER(c_double)), count)
like image 77
HYRY Avatar answered Oct 10 '22 11:10

HYRY