I am using ngCropImage to crop an image and want to upload it following this link:
NgCropImage directive is returning me dataURI of the image and I am converting it to a blob (after converting it I get a blob object: which has size and type), Converted DataURI to blob using following code:
/*html*/
<img-crop image="myImage" result-image="myCroppedImage" result-image-size="250"></img-crop>
$scope.myImage='';
$scope.myCroppedImage = {image: ''}
var blob;
//called when user crops
var handleFileSelect=function(evt) {
var file=evt.currentTarget.files[0];
var reader = new FileReader();
reader.onload = function (evt) {
$scope.$apply(function($scope){
$scope.myImage=evt.target.result;
});
};
console.log($scope.myCroppedImage)
reader.readAsDataURL(file);
var link = document.createElement('link');
blob = dataURItoBlob($scope.myCroppedImage)
console.log(blob)
};
angular.element(document.querySelector('#fileInput')).on('change',handleFileSelect);
function dataURItoBlob(dataURI) {
// convert base64/URLEncoded data component to raw binary data held in a string
var binary = atob(dataURI.split(',')[1]);
var mimeString = dataURI.split(',')[0].split(':')[1].split(';')[0];
var array = [];
for(var i = 0; i < binary.length; i++) {
array.push(binary.charCodeAt(i));
}
return new Blob([new Uint8Array(array)], {type: mimeString});
}
$scope.upload = function(file) {
//var file = new File(file, "filename");
// Configure The S3 Object
console.log($scope.creds)
AWS.config.update({ accessKeyId: $.trim($scope.creds.access_key), secretAccessKey: $.trim($scope.creds.secret_key) });
AWS.config.region = 'us-east-1';
var bucket = new AWS.S3({ params: { Bucket: $.trim($scope.creds.bucket) } });
if(file) {
//file.name = 'abc';
var uniqueFileName = $scope.uniqueString() + '-' + file.name;
var params = { Key: file.name , ContentType: file.type, Body: file, ServerSideEncryption: 'AES256' };
bucket.putObject(params, function(err, data) {
if(err) {
// There Was An Error With Your S3 Config
alert(err.message);
return false;
}
else {
// Success!
alert('Upload Done');
}
})
.on('httpUploadProgress',function(progress) {
// Log Progress Information
console.log(Math.round(progress.loaded / progress.total * 100) + '% done');
});
}
else {
// No File Selected
alert('No File Selected');
}
}
$scope.uniqueString = function() {
var text = "";
var possible = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789";
for( var i=0; i < 8; i++ ) {
text += possible.charAt(Math.floor(Math.random() * possible.length));
}
return text;
}
//for uploading
$scope.handleSave = function(){
$scope.upload(blob);
}
Now, I want to upload this blob on S3 using this, but I am not able to figure out how to upload this blob file to s3 (as I am not getting 'name' in the blob file)
Any help would be really appreciated. Thanks
To upload folders and files to an S3 bucketSign in to the AWS Management Console and open the Amazon S3 console at https://console.aws.amazon.com/s3/ . In the Buckets list, choose the name of the bucket that you want to upload your folders or files to. Choose Upload.
AWS object storage comes in the form of Amazon S3, or Simple Storage Service, and Azure object storage is available with Azure Blob Storage. Both Amazon S3 and Azure Blob Storage are massively scalable object storage services for unstructured data. Object storage has all the data stored together.
To upload a file to an S3 bucket, use the TransferUtility class. When uploading data from a file, you must provide the object's key name. If you don't, the API uses the file name for the key name.
Upload your CSV files to an Amazon Simple Storage Service ( Amazon S3) bucket. This is the location that Amazon Personalize imports your data from. For more information, see Uploading Files and Folders by Using Drag and Drop in the Amazon Simple Storage Service User Guide.
You can always create file from blob. You can pass file name also.
var file = new File([blob], "filename");
This same file object you can use to upload on s3.
Change your handleSave method to following. File name will be abc.png for now
//for uploading
$scope.handleSave = function(){
blob = dataURItoBlob($scope.myCroppedImage)
$scope.upload(new File([blob], "abc.png"));
}
It is not advisable that you do to put the key
secretAccessKey: $.trim($scope.creds.secret_key)
on the client side ... That is not done !, anyone can manipulate your bucket at will.
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