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Angular $q returning promise multiple $http calls

I'm working on an $http call that loops over each of multiple api's and returns all of the data in one object. I usually have the promise ready to resolve when the $http call has been made. Similar to this:

function getAllData(api) {
    return $http({
        method: 'GET',
        url: '/api/' + api
    })
    .then(sendResponseData)
    .catch (sendGetVolunteerError);
}

The current function I have loops over each api and pushes each object in the api into an array and then pushes it into an overall array. I had this functioning, returning an multi-dimensional array, which needed to be flattened out.

I'd like to return this in a promise, but am returning undefined. Here is what I have so far? Is there a better way to approach this?

dataService:

function getSearchData() {
    return {
        loadDataFromUrls: function () {
            var apiList = ["abo", "ser", "vol", "con", "giv", "blo", "par"];
            var deferred = $q.defer();
            var log = [];
            angular.forEach(apiList, function (item, key) {
                var logNew = [];
                $http({
                    method: 'GET',
                    url: '/api/' + item
                }).then(function (response) {
                    angular.forEach(response.data, function (item, key) {
                        this.push(item);
                    }, logNew);
                    return logNew;
                });
                this.push(logNew);
            }, log);
            $q.all(log).then(

            function (results) {
                deferred.resolve(
                JSON.stringify(results))
            },

            function (errors) {
                deferred.reject(errors);
            },

            function (updates) {
                deferred.update(updates);
            });
            return deferred.promise;
        }
    };
};

Controller:

function getSearchData(){
  return dataService.getSearchData.loadDataFromUrls;
}  

$scope.searchData = getSearchData();
like image 389
byrdr Avatar asked Mar 20 '15 14:03

byrdr


2 Answers

$q.all and a map function are what you need here:

function getSearchData() {
    return {
        // returns a promise for an object like:
        // { abo: resultFromAbo, ser: resultFromSer, ... }
        loadDataFromUrls: function () {
            var apiList = ["abo", "ser", "vol", "con", "giv", "blo", "par"];

            return $q.all(apiList.map(function (item) {
                return $http({
                    method: 'GET',
                    url: '/api/' + item
                });
            }))
            .then(function (results) {
                var resultObj = {};
                results.forEach(function (val, i) {
                    resultObj[apiList[i]] = val.data;
                });
                return resultObj;        
            });
        }
    };
}
like image 93
JLRishe Avatar answered Oct 13 '22 21:10

JLRishe


If you have an arbitrary set of api calls I would do something like this:

function getSearchData(){
    var deferred = $q.defer();
    var noOfCalls = apiList.length;
    var results = [];
    var called = 0;

    angular.forEach(apiList, function(item, key) {
        $http.get(url).then(function(result){
           results.push(result);
           called++;
           if(called == noOfCalls){
              deferred.resolve(results);
           }     
        })
   });

    return deferred.promise;
}

However if you know what each api call represents its better to use $.all in this way

function search1(){
      return $http.get(search1Url).then(function(result){
          // do something to it
          return result; 
      });
}

function search2(){
      return $http.get(search2Url).then(function(result){
          // do something to it
          return result; 
      });
}

function search3(){
      return $http.get(search3Url).then(function(result){
          // do something to it
          return result; 
      });
}

function search4(){
      return $http.get(search4Url).then(function(result){
          // do something to it
          return result; 
      });
}

function getSearchResult(){

    return $q.all([search1(), search2(), search3(), search4()]).then(function(results){
       // OPTIONAL  aggregate results before resolving
       return results;
    });
}
like image 37
Chris Noring Avatar answered Oct 13 '22 21:10

Chris Noring