Upload video to Youtube using Youtube API V3 and PHP

Question

I am trying to upload a video to Youtube using PHP. I am using Youtube API v3 and I am using the latest checked out source code of Google API PHP Client library.
I am using the sample code given on
https://code.google.com/p/google-api-php-client/ to perform the authentication. The authentication goes through fine but when I try to upload a video I get Google_ServiceException with error code 500 and message as null.

I had a look at the following question asked earlier: Upload video to youtube using php client library v3 But the accepted answer doesn't describe how to specify file data to be uploaded.
I found another similar question Uploading file with Youtube API v3 and PHP, where in the comment it is mentioned that categoryId is mandatory, hence I tried setting the categoryId in the snippet but still it gives the same exception.

I also referred to the Python code on the the documentation site ( https://developers.google.com/youtube/v3/docs/videos/insert ), but I couldn't find the function next_chunk in the client library. But I tried to put a loop (mentioned in the code snippet) to retry on getting error code 500, but in all 10 iterations I get the same error.

Following is the code snippet I am trying:

$youTubeService = new Google_YoutubeService($client);
if ($client->getAccessToken()) {
    print "Successfully authenticated";
    $snippet = new Google_VideoSnippet();
    $snippet->setTitle = "My Demo title";
    $snippet->setDescription = "My Demo descrition";
    $snippet->setTags = array("tag1","tag2");
    $snippet->setCategoryId(23); // this was added later after refering to another question on stackoverflow

    $status = new Google_VideoStatus();
    $status->privacyStatus = "private";

    $video = new Google_Video();
    $video->setSnippet($snippet);
    $video->setStatus($status);

    $data = file_get_contents("video.mp4"); // This file is present in the same directory as the code
    $mediaUpload = new Google_MediaFileUpload("video/mp4",$data);
    $error = true;
    $i = 0;

    // I added this loop because on the sample python code on the documentation page
    // mentions we should retry if we get error codes 500,502,503,504
    $retryErrorCodes = array(500, 502, 503, 504);
    while($i < 10 && $error) {
        try{
            $ret = $youTubeService->videos->insert("status,snippet", 
                                                   $video, 
                                                   array("data" => $data));

            // tried the following as well, but even this returns error code 500,
            // $ret = $youTubeService->videos->insert("status,snippet", 
            //                                        $video, 
            //                                        array("mediaUpload" => $mediaUpload); 
            $error = false;
        } catch(Google_ServiceException $e) {
            print "Caught Google service Exception ".$e->getCode()
                  . " message is ".$e->getMessage();
            if(!in_array($e->getCode(), $retryErrorCodes)){
                break;
            }
            $i++;
        }
    }
    print "Return value is ".print_r($ret,true);

    // We're not done yet. Remember to update the cached access token.
    // Remember to replace $_SESSION with a real database or memcached.
    $_SESSION['token'] = $client->getAccessToken();
} else {
    $authUrl = $client->createAuthUrl();
    print "<a href='$authUrl'>Connect Me!</a>";
}

Is it something that I am doing wrong?

Answer 1

I was able to get the upload working using the following code:

if($client->getAccessToken()) {     $snippet = new Google_VideoSnippet();     $snippet->setTitle("Test title");     $snippet->setDescription("Test descrition");     $snippet->setTags(array("tag1","tag2"));     $snippet->setCategoryId("22");      $status = new Google_VideoStatus();     $status->privacyStatus = "private";      $video = new Google_Video();     $video->setSnippet($snippet);     $video->setStatus($status);      $error = true;     $i = 0;      try {         $obj = $youTubeService->videos->insert("status,snippet", $video,                                          array("data"=>file_get_contents("video.mp4"),                                          "mimeType" => "video/mp4"));     } catch(Google_ServiceException $e) {         print "Caught Google service Exception ".$e->getCode(). " message is ".$e->getMessage(). " <br>";         print "Stack trace is ".$e->getTraceAsString();     } } 

Answer 2

I realize this is old, but here's the answer off the documentation:

    // REPLACE this value with the path to the file you are uploading.     $videoPath = "/path/to/file.mp4";      $snippet = new Google_Service_YouTube_VideoSnippet();     $snippet->setTitle("Test title");     $snippet->setDescription("Test description");     $snippet->setTags(array("tag1", "tag2"));      // Numeric video category. See     // https://developers.google.com/youtube/v3/docs/videoCategories/list      $snippet->setCategoryId("22");      // Set the video's status to "public". Valid statuses are "public",     // "private" and "unlisted".     $status = new Google_Service_YouTube_VideoStatus();     $status->privacyStatus = "public";      // Associate the snippet and status objects with a new video resource.     $video = new Google_Service_YouTube_Video();     $video->setSnippet($snippet);     $video->setStatus($status);      // Specify the size of each chunk of data, in bytes. Set a higher value for     // reliable connection as fewer chunks lead to faster uploads. Set a lower     // value for better recovery on less reliable connections.     $chunkSizeBytes = 1 * 1024 * 1024;      // Setting the defer flag to true tells the client to return a request which can be called     // with ->execute(); instead of making the API call immediately.     $client->setDefer(true);      // Create a request for the API's videos.insert method to create and upload the video.     $insertRequest = $youtube->videos->insert("status,snippet", $video);      // Create a MediaFileUpload object for resumable uploads.     $media = new Google_Http_MediaFileUpload(         $client,         $insertRequest,         'video/*',         null,         true,         $chunkSizeBytes     );     $media->setFileSize(filesize($videoPath));       // Read the media file and upload it chunk by chunk.     $status = false;     $handle = fopen($videoPath, "rb");     while (!$status && !feof($handle)) {       $chunk = fread($handle, $chunkSizeBytes);       $status = $media->nextChunk($chunk);     }      fclose($handle);      // If you want to make other calls after the file upload, set setDefer back to false     $client->setDefer(false); 

Answer 3

I also realize this is old, but as I cloned the latest version of php-client from GitHub I ran in to trouble with Google_Service_YouTube_Videos_Resource::insert()-method.

I would pass an array with "data" => file_get_contents($pathToVideo) and "mimeType" => "video/mp4" set as an argument for the insert()-method, but I still kept getting (400) BadRequest in return.

Debugging and reading through Google's code i found in \Google\Service\Resource.php there was a check (on lines 179-180) against an array key "uploadType" that would initiate the Google_Http_MediaFielUpload object.

$part = 'status,snippet';
$optParams = array(
    "data" => file_get_contents($filename),
    "uploadType" => "media",  // This was needed in my case
    "mimeType" => "video/mp4",
);
$response = $youtube->videos->insert($part, $video, $optParams);

If I remember correctly, with version 0.6 of the PHP-api the uploadType argument wasn't needed. This might apply only for the direct upload style and not the resumable upload shown in Any Day's answer.