I have a table in MS SQL Server, where are some null values in column "value"
Group ID Value
A 1 10
A 2
A 3
A 4 40
B 1
B 2 20
B 3 30
B 4
I want to update null values by not null in the same group with with the first higher ID, or if there is not any higher in same group, first lower. So the result should look like this.
Group ID Value
A 1 10
A 2 40
A 3 40
A 4 40
B 1 20
B 2 20
B 3 30
B 4 30
Thanks!
You can use windowed version of SUM
function in order to determine islands of NULL
valued records along with the record having the higher ID in the same group:
SELECT [Group], ID, Value,
SUM(CASE WHEN Value IS NULL THEN 0 ELSE 1 END) OVER
(PARTITION BY [Group] ORDER BY ID DESC) AS grp
FROM mytable
Output:
Group ID Value grp
-----------------------
A 4 40 1
A 3 30 2
A 2 NULL 2
A 1 NULL 2
B 4 40 1
B 3 NULL 1
B 2 20 2
B 1 10 3
You can now wrap the above query in a CTE
and use another CTE
to do the update:
;WITH CTE AS (
SELECT [Group], ID, Value,
SUM(CASE WHEN Value IS NULL THEN 0 ELSE 1 END) OVER
(PARTITION BY [Group] ORDER BY ID DESC) AS grp
FROM mytable
), ToUpdate AS (
SELECT [Group], ID, Value,
MAX(Value) OVER (PARTITION BY [Group], grp) AS group_value
FROM CTE
)
UPDATE ToUpdate
SET Value = group_value
WHERE Value IS NULL
Demo here
Edit:
The above query doesn't handle the edge case where the very last record within a Group
slice is NULL
. To handle this case as well you can use the following query:
;WITH CTE AS (
SELECT [Group], ID, Value,
SUM(CASE WHEN Value IS NULL THEN 0 ELSE 1 END) OVER
(PARTITION BY [Group] ORDER BY ID DESC) AS grp,
SUM(CASE WHEN Value IS NULL THEN 0 ELSE 1 END) OVER
(PARTITION BY [Group] ORDER BY ID) AS grp2
FROM mytable
), ToUpdate AS (
SELECT [Group], ID, Value,
MAX(Value) OVER (PARTITION BY [Group], grp) AS group_value,
MAX(Value) OVER (PARTITION BY [Group], grp2) AS group_value2
FROM CTE
)
UPDATE ToUpdate
SET Value = COALESCE(group_value, group_value2)
WHERE Value IS NULL
Demo here
Please try this-
DATA GENERATION
DECLARE @T TABLE
(
GroupCd CHAR(1),
Id INT,
Value INT
)
INSERT INTO @T
VALUES('A',1,10),
('A',2,NULL),
('A',3,NULL),
('A',4,40),
('B',1,NULL),
('B',2,20),
('B',3,30),
('B',4,NULL)
SOLUTION
UPDATE a
SET a.Value = b.Value
FROM @T a
INNER JOIN
(
SELECT a.GroupCd,a.Id,Coalesce(a.Value,z.Value,z1.Value) Value
FROM @T a
OUTER APPLY
(
SELECT TOP 1 Value
FROM @T b
WHERE a.GroupCd = b.GroupCd
AND b.Value IS NOT NULL AND a.Id < b.Id
ORDER BY Id
)z
OUTER APPLY
(
SELECT TOP 1 Value
FROM @T b
WHERE a.GroupCd = b.GroupCd
AND b.Value IS NOT NULL AND a.Id > b.Id
ORDER BY Id DESC
)z1
)b ON a.GroupCd = b.GroupCd AND a.Id = b.Id
SELECT * FROM @T
OUTPUT
GroupCd Id Value
------- ----------- -----------
A 1 10
A 2 40
A 3 40
A 4 40
B 1 20
B 2 20
B 3 30
B 4 30
(8 rows affected)
You Can try This simple Method
DECLARE @T TABLE
(
GroupCd CHAR(1),
Id INT,
Value INT
)
INSERT INTO @T
VALUES('A',1,NULL),
('A',2,NULL),
('A',3,30),
('A',4,40),
('B',1,10),
('B',2,20),
('B',3,NULL),
('B',4,40)
SELECT
*,
NewVal = COALESCE(Value,(SELECT TOP 1 Value FROM @T WHERE GroupCd = T.GroupCd AND Id > T.Id AND Value IS NOT NULL ORDER BY Id ASC))
FROM @T T
My Result
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