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I have a variable unsigned char that contains a value, 40 for example. I want a int variable to get that value. What's the simplest and most efficient way to do that? Thank you very much.
200
unsigned char is essentially a one byte of memory interpreted by the computer as an integer it is from 0 to 255.
We can convert char to int by negating '0' (zero) character. char datatype is represented as ascii values in c programming. Ascii values are integer values if we negate the '0' character then we get the ascii of that integer digit.
unsigned char is a character datatype where the variable consumes all the 8 bits of the memory and there is no sign bit (which is there in signed char). So it means that the range of unsigned char data type ranges from 0 to 255.
Beside the char type in C , there is also the unsigned char , and the signed char types . All three types are different , but they have the same size of 1 byte . The unsigned char type can only store nonnegative integer values , it has a minimum range between 0 and 127 , as defined by the C standard.
unsigned char c = 40;
int i = c;
Presumably there must be more to your question than that...
114
Try one of the followings, it works for me. If you need more specific cast, you can check Boost's lexical_cast and reinterpret_cast.
unsigned char c = 40;
int i = static_cast<int>(c);
std::cout << i << std::endl;
or:
unsigned char c = 40;
int i = (int)(c);
std::cout << i << std::endl;
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