How can CString be passed to format string %s?

Question

class MyString
{
public:
    MyString(const std::wstring& s2)
    {
        s = s2;
    }

    operator LPCWSTR() const
    {
        return s.c_str();
    }
private:
    std::wstring s;
};

int _tmain(int argc, _TCHAR* argv[])
{
    MyString s = L"MyString";
    CStringW cstring = L"CString";
    wprintf(L"%s\n", (LPCWSTR)cstring); // Okay. Becase it has an operator LPCWSTR()
    wprintf(L"%s\n", cstring); // Okay, fine. But how?        
    wprintf(L"%s\n", (LPCWSTR)s); // Okay. fine.
    wprintf(L"%s\n", s); // Doesn't work. Why? It prints gabage string like "?."
    return 0;
}

How can CString be passed to format string %s?

By the way, MSDN says(it's weird)

To use a CString object in a variable argument function
Explicitly cast the CString to an LPCTSTR string, as shown here:

CString kindOfFruit = "bananas";
int      howmany = 25;
printf( "You have %d %s\n", howmany, (LPCTSTR)kindOfFruit ); 

Answer 1

CString is specifically designed such that it only contains a pointer that points to the string data in a buffer class. When passed by value to printf it will be treated as a pointer when seeing the "%s" in the format string.

It originally just happened to work with printf by chance, but this has later been kept as part of the class interface.

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This post is based on MS documentation long since retired, so I cannot link to their promise that they will continue to make this work.

However, before adding more downvotes please also read this blog post from someone sharing my old knowledge:

Big Brother helps you