Is there an equivalent to the unless
statement in Python? I do not want to append a line to a label if it has p4port
in it:
for line in newLines:
if 'SU' in line or 'AU' in line or 'VU' in line or 'rf' in line and line.find('/*') == -1:
lineMatch = False
for l in oldLines:
if '@' in line and line == l and 'p4port' not in line:
lineMatch = True
line = line.strip('\n')
line = line.split('@')[1]
line = line + '<br>\n'
labels.append(line)
if '@' in line and not lineMatch:
line = line.strip('\n')
line = line.split('@')[1]
line="<font color='black' style='background:rgb(255, 215, 0)'>"+line+"</font><br>\n"
labels.append(line)
I get a Syntax error:
if '@' in line and not lineMatch:
UnboundLocalError: local variable 'lineMatch' referenced before assignment
The % symbol in Python is called the Modulo Operator. It returns the remainder of dividing the left hand operand by right hand operand.
If Statement The statement can be a single line or a block of code. #If the condition is true, the statement will be executed. num = 5 if num > 0: print(num, "is a positive number.") print("This statement is true.") #When we run the program, the output will be: 5 is a positive number. This statement is true.
What about 'not in'?:
if 'p4port' not in line: labels.append(line)
Also i guess that you code can be modified then to:
if '@' in line and line == l and 'p4port' not in line: lineMatch = True labels.append(line.strip('\n').split('@')[1] + '<br>\n')
There's no "unless" statement, but you can always write:
if not some_condition: # do something
There's also the not in
operator as Artsiom mentioned - so for your code, you'd write:
if '@' in line and line == l: lineMatch = True line = line.strip('\n') line = line.split('@')[1] line = line + '<br>\n' if 'p4port' not in line: labels.append(line)
... but Artsiom's version is better, unless you plan to do something with your modified line
variable later.
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