Unix: sort by last number of line

Question

How do you sort a file by the last number in a line?

Assuming the last character of every line is a number. INPUT:

facebook.com/pageA,2,11,11
facebook.com/pageB,0,0,20
facebook.com/pageC,0,0,6
facebook.com/pageD,1,22,239

Desired Output:

facebook.com/pageC,0,0,6
facebook.com/pageA,2,11,11
facebook.com/pageB,0,0,20
facebook.com/pageD,1,22,239

Help??

Answer 1

You can use sort.

sort -n -t, -k4 INPUT

Answer 2

If your input file has different columns in each line then you can make the last column as first column, sort by it and then remove it.

awk '{print($NF,$0)}' FS=, OFS=, inputFile | sort -t, -nk1 | cut -f2- -d,

Answer 3

Use rev to reverse each line, then sort, then re-reverse:

rev < $file | sort | rev