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If you just need the average size in bytes, you can use find . -type f -exec stat -f%z {} +|awk '{s+=$0}END{print s/NR}' .
don't worry we have a got a UNIX command to do that for you and command is "df" which displays the size of the file system in UNIX. You can run "df" UNIX command with the current directory or any specified directory.
Locate the file or folder whose size you would like to view. Click the file or folder. Press Command + I on your keyboard. A window opens and shows the size of the file or folder.
Using the ls Command –l – displays a list of files and directories in long format and shows the sizes in bytes. –h – scales file sizes and directory sizes into KB, MB, GB, or TB when the file or directory size is larger than 1024 bytes. –s – displays a list of the files and directories and shows the sizes in blocks.
I found something here:
http://vivekjain10.blogspot.com/2008/02/average-file-size-within-directory.html
To calculate the average file size within a directory on a Linux system, following command can be used:
ls -l | gawk '{sum += $5; n++;} END {print sum/n;}'
A short, general and recursion-friendly variation of Ernstsson's answer:
find ./ -ls | awk '{sum += $7; n++;} END {print sum/n;}'
Or, for example, if you want to impede files above 100 KB from stewing the average:
find ./ -size -100000c -ls | awk '{sum += $7; n++;} END {print sum/n;}'
Use wc -c * to get the size of all the files and ls | wc -l to get the number of files. Then just divide one by the other.
du -sh . # gives the total space used by the directory
find . -type f | wc -l # count the number of files
devide the first by the second. If you want a one liner, here it is:
echo $(( `du -sb | tr '.' ' '` / `find . -type f | wc -l` ))
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