Unique values of array in swift [duplicate]

Question

I'm building an iOS app with swift and i need to get all unique values of array of strings.

I've been reading the apple developer docs but it doesn't seem to have a function for it.

Can someone give me an hint?

Answer 1

There might be a more efficient way, but an extension would probably be most straightforward:

extension Array where Element: Equatable {     var unique: [Element] {         var uniqueValues: [Element] = []         forEach { item in             guard !uniqueValues.contains(item) else { return }             uniqueValues.append(item)         }         return uniqueValues     } } 

If order doesn't matter and objects are also hashable:

let array = ["one", "one", "two", "two", "three", "three"] // order NOT guaranteed let unique = Array(Set(array)) // ["three", "one", "two"] 

Answer 2

There isn't a function to do this in the Swift standard library, but you could write one:

extension Sequence where Iterator.Element: Hashable {     func unique() -> [Iterator.Element] {         var seen: [Iterator.Element: Bool] = [:]         return self.filter { seen.updateValue(true, forKey: $0) == nil }     } }  let a = ["four","one", "two", "one", "three","four", "four"] a.unique // ["four", "one", "two", "three"] 

This has the downside of requiring the contents of the sequence to be hashable, not just equatable, but then again most equatable things are, including strings.

It also preserves the original ordering unlike, say, putting the contents in a dictionary or set and then getting them back out again.