I've got a class representing an interval. This class has two properties "start" and "end" of a comparable type. Now I'm searching for an efficient algorithm to take the union of a set of such intervals.
Thanks in advance.
Unions: Any union of intervals with a common point is an interval.
The union of two sets is a set containing all elements that are in A or in B (possibly both). For example, {1,2}∪{2,3}={1,2,3}. Thus, we can write x∈(A∪B) if and only if (x∈A) or (x∈B). Note that A∪B=B∪A.
Sort them by one of the terms (start, for example), then check for overlaps with its (right-hand) neighbor as you move through the list.
class tp:
def __repr__(self):
return "(%d,%d)" % (self.start, self.end)
def __init__(self, start, end):
self.start = start
self.end = end
s = [tp(5, 10), tp(7, 8), tp(0, 5)]
s.sort(key=lambda self: self.start)
y = [s[0]]
for x in s[1:]:
if y[-1].end < x.start:
y.append(x)
elif y[-1].end == x.start:
y[-1].end = x.end
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