Unicode value \uXXXX to Character in Javascript

Question

I've never done this before and am not sure why it's outputting the infamous � encoding character. Any ideas on how to output characters as they should (ASCII+Unicode)? I think \u0041-\u005A should print A-Z in UTF-8, which Firefox is reporting is the page encoding.

   var c   = new Array("F","E","D","C","B","A",9,8,7,6,5,4,3,2,1,0);
   var n   = 0;
   var d   = "";
   var o   = "";

   for (var i=16;i--;){
      for (var j=16;j--;){
         for (var k=16;k--;){
            for (var l=16;l--;){

               d =  c[i].toString()
                 +  c[j].toString()
                 +  c[k].toString()
                 +  c[l].toString();

               o += ( ++n + ": " 
                    + d   + " = " 
                    + String.fromCharCode("\\u" + d) 
                    + "\n<br />" );

               if(n>=500){i=j=k=l=0;} // stop early
            }
         }
      }
   }

   document.write(o);

Answer 1

The .fromCharCode() function takes a number, not a string. You can't put together a string like that and expect the parser to do what you think it'll do; that's just not the way the language works.

You could ammend your code to make a string (without the '\u') from your hex number, and call

var n = parseInt(hexString, 16);

to get the value. Then you could call .fromCharCode() with that value.

Answer 2

A useful snippet for replacing all unicode-encoded special characters in a text is:

var rawText = unicodeEncodedText.replace(
                  /\\u([0-9a-f]{4})/g, 
                  function (whole, group1) {
                      return String.fromCharCode(parseInt(group1, 16));
                  }
              );

Using replace, fromCharCode and parseInt