I've run the below java code to get time difference.
import java.text.SimpleDateFormat;
import java.util.Calendar;
import java.util.Date;
import java.util.TimeZone;
public class Test
{
public static SimpleDateFormat simpleDateFormat= new SimpleDateFormat("yyyy-MM-dd hh:mm:ss");
public static Date date1,date2;
public static long diff;
public static String TAG ="DateConversion";
public static Calendar cal1,cal2;
public static void main(String a[])
{
checkTimeDifference("2013-10-30 10:15:00", "2013-10-30 11:15:00");
checkTimeDifference("2013-10-30 10:15:00", "2013-10-30 12:15:00");
checkTimeDifference("2013-10-30 10:15:00", "2013-10-30 13:15:00");
}
public static void checkTimeDifference(String strDate,String checkDate)
{
try
{
simpleDateFormat.setTimeZone(TimeZone.getTimeZone("GMT"));
date1 = simpleDateFormat.parse(strDate);
date2 = simpleDateFormat.parse(checkDate);
//in milliseconds
diff = date2.getTime() - date1.getTime();
System.out.println("Difference : "+diff);
long diffSeconds = diff / 1000 % 60;
long diffMinutes = diff / (60 * 1000) % 60;
long diffHours = diff / (60 * 60 * 1000) % 24;
long diffDays = diff / (24 * 60 * 60 * 1000);
System.out.println(diffDays + " days, ");
System.out.println(diffHours + " hours, ");
System.out.println(diffMinutes+ " minutes, ");
System.out.println(diffSeconds+ " seconds.");
}
catch (Exception e)
{
System.out.println(""+e);
}
}
}
the output of above program is.,
Difference : 3600000
0 days,
1 hours,
0 minutes,
0 seconds.
Difference : -36000000
0 days,
-10 hours,
0 minutes,
0 seconds.
Difference : 10800000
0 days,
3 hours,
0 minutes,
0 seconds.
its return minus value when executing "checkTimeDifference("2013-10-30 10:15:00", "2013-10-30 12:15:00");"
why its return minus value and how to solve it?
This is the problem:
new SimpleDateFormat("yyyy-MM-dd hh:mm:ss")
The hh
here means "12 hour hour-of-day" so 12 means midnight unless there's something to indicate that it's meant to be 12 PM. Your value of 13 only works because the parser is in a lenient mode. You want:
new SimpleDateFormat("yyyy-MM-dd HH:mm:ss")
I'd also strongly advise you to use Joda Time for this task anyway, as it makes it a lot simpler.
Changing the SimpleDateFormat
pattern to yyyy-MM-dd HH:mm:ss
fixes the issues.
This happens because in the yyyy-MM-dd hh:mm:ss
case, 12
is evaluated as 0
.
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