Unescaping escaped characters in a string using Python 3.2

Question

Say I have a string in Python 3.2 like this:

'\n'

When I print() it to the console, it shows as a new line, obviously. What I want is to be able to print it literally as a backslash followed by an n. Further, I need to do this for all escaped characters, such as \t. So I'm looking for a function unescape() that, for the general case, would work as follows:

>>> s = '\n\t'
>>> print(unescape(s)) 
'\\n\\t'

Is this possible in Python without constructing a dictionary of escaped characters to their literal replacements?

(In case anyone is interested, the reason I am doing this is because I need to pass the string to an external program on the command line. This program understands all the standard escape sequences.)

Answer 1

To prevent special treatment of \ in a literal string you could use r prefix:

s = r'\n'
print(s)
# -> \n

If you have a string that contains a newline symbol (ord(s) == 10) and you would like to convert it to a form suitable as a Python literal:

s = '\n'
s = s.encode('unicode-escape').decode()
print(s)
# -> \n