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In django, I defined url like that
(r'^checkstring/(?P<string>\w+)/$',views.check_str,name='check str')
But, When i enter string inputs like ibrahim.yilmaz, ibrahi!m or [email protected], it returns http 404. So how can i write the url which accept everykind of string?
any help will be appreciated.
İbrahim
212
import views urlpatterns = [ path('blog/', views. page), path('blog/page<int:num>/', views. page), ] # View (in blog/views.py) def page(request, num=1): # Output the appropriate page of blog entries, according to num. ... In the above example, both URL patterns point to the same view – views.
Being able to capture one or more values from a given URL during an HTTP request is an important feature Django offers developers. We already saw a little bit about how Django routing works, but those examples used hard-coded URL patterns. While this does work, it does not scale.
How does Django treat a request URL string? Django runs through each URL pattern, in order, and stops at the first one that matches the requested URL, matching against path_info . Once one of the URL patterns matches, Django imports and calls the given view, which is a Python function (or a class-based view).
Django uses regular expressions to match incoming requests. In python a dot (.) matches any character except a newline. See docs for more information and try:
(r'^checkstring/(?P<string>.+)/$',views.check_str,name='check str')
Also keep in mind that this will accept any character (including the forward slash) which may not be desirable for you. Be sure to test to make sure everything works as you would expect.
185
In Django >= 2.0, you can implement in the following way.
from django.urls import path
urlpatterns = [
...
path('polls/<string>/$','polls.views.detail')
...
]
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