Understanding the output of typeid().name()

Question

I was checking some types of variables and got some confusing results:

#include <iostream>
#include <typeinfo>
using namespace std;

int main(void) {
    int number = 5;
    int* pointer = &number;

    cout << typeid(number).name() << endl;      // i
    cout << typeid(pointer).name() << endl;     // Pi
    cout << typeid(&pointer).name() << endl;    // PPi

    return 0;
}

The i means int, but what do Pi and PPi mean? Pointer int?

Answer 1

It means pointer to an integer and pointer to a pointer to an integer, respectively.

Answer 2

• i: integer
• Pi: pointer to integer variable
• Ppi: pointer to a pointer to integer variable