Understanding private methods in Ruby

Question

Here's the short and the long of it. What private means in Ruby is a method cannot be called with an explicit receivers, e.g. some_instance.private_method(value). So even though the implicit receiver is self, in your example you explicitly use self so the private methods are not accessible.

Think of it this way, would you expect to be able to call a private method using a variable that you have assigned to an instance of a class? No. Self is a variable so it has to follow the same rules. However when you just call the method inside the instance then it works as expected because you aren't explicitly declaring the receiver.

Ruby being what it is you actually can call private methods using instance_eval:

class Foo
  private
  def bar(value)
    puts "value = #{value}"
  end
end

f = Foo.new
begin
  f.bar("This won't work")
rescue Exception=>e
  puts "That didn't work: #{e}"
end
f.instance_eval{ bar("But this does") }

Hope that's a little more clear.

-- edit --

I'm assuming you knew this will work:

class Foo
 def public_m
  private_m # Removed self.
 end
 private
 def private_m
  puts 'Hello'
 end
end

Foo.new.public_m

The definition of private in Ruby is "can only be called without an explicit receiver". And that's why you can only call private methods without an explicit receiver. There is no other explanation.

Note that there actually is an exception to the rule: because of the ambiguity between local variables and method calls, the following will always be resolved to be an assignment to a local variable:

foo = :bar

So, what do you do if you want to call a writer called foo=? Well, you have to add an explicit receiver, because without the receiver Ruby simply won't know that you want to call the method foo= instead of assigning to the local variable foo:

self.foo = :bar

But what do you do if you want to call a private writer called foo=? You can't write self.foo = because foo= is private and thus cannot be called with an explicit receiver. Well, actually for this specific case (and this case alone), you can actually use an explicit receiver of self to call a private writer.

It's weird, but many things about Ruby's visibility modifiers are weird. Even if self is the implicit receiver, actually spelling it out makes it explicit in the eyes of the Ruby runtime. When it says that private methods cannot be called with an explicit receiver, that is what it means, even self counts.

IIRC, private methods allow only implicit receiver (which is always self, of course).

Sorry for my prevoius answer. I just don't understand your question.

I changed your code like this:

class Foo
 def public_m
  private_m # <=
 end

 def Foo.static_m
   puts "static"
 end

 def self.static2_m
   puts "static 2"
 end

 private 
 def private_m
  puts 'Hello'
 end
end

Foo.new.public_m
Foo.static_m
Foo.static2_m

Here is a call of instance method:

 def public_m
  private_m # <=
 end

Here are a call of class methods:

 def Foo.static_m
   puts "static"
 end

 def self.static2_m
   puts "static 2"
 end

Foo.static_m
Foo.static2_m