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Understanding NumPy's Convolve

When calculating a simple moving average, numpy.convolve appears to do the job.

Question: How is the calculation done when you use np.convolve(values, weights, 'valid')?

When the docs mentioned convolution product is only given for points where the signals overlap completely, what are the 2 signals referring to?

If any explanations can include examples and illustrations, it will be extremely useful.

window = 10
weights = np.repeat(1.0, window)/window
smas = np.convolve(values, weights, 'valid')
like image 960
Nyxynyx Avatar asked Nov 17 '13 21:11

Nyxynyx


People also ask

How does NP convolve work?

The np. convolve() is a built-in numpy library method used to return discrete, linear convolution of two one-dimensional vectors. The numpy convolve() method accepts three arguments which are v1, v2, and mode, and returns discrete the linear convolution of v1 and v2 one-dimensional vectors.

What does it mean to convolve two arrays?

Convolution is a simple mathematical operation which is fundamental to many common image processing operators. Convolution provides a way of `multiplying together' two arrays of numbers, generally of different sizes, but of the same dimensionality, to produce a third array of numbers of the same dimensionality.

What does SciPy convolve do?

The same concept of convolving is used in Python. The array is considered as a signal which is used in the SciPy Convolve function to perform convolution over multiple one-dimensional arrays. The SciPy Convolve is an N-dimensional array. It is usually two or more 1-D sequences.

How do you use convolve in Python?

Convolution is an operation that is performed on an image to extract features from it applying a smaller tensor called a kernel like a sliding window over the image. Depending on the values in the convolutional kernel, we can pick up specific patterns from the image.

What does convolve () do in NumPy?

numpy.convolve(a, v, mode='full') [source] ¶ Returns the discrete, linear convolution of two one-dimensional sequences. The convolution operator is often seen in signal processing, where it models the effect of a linear time-invariant system on a signal.

Which array acts as the signal in NumPy convolution?

An array in numpy acts as the signal. The np.convolve () is a built-in numpy library method used to return discrete, linear convolution of two one-dimensional vectors. The numpy convolve () method accepts three arguments which are v1, v2, and mode, and returns discrete the linear convolution of v1 and v2 one-dimensional vectors.

How to convolve two one-dimensional vectors using NumPy?

This method convolve () in the numpy module returns the discrete linear convolution of two one dimensional vectors. Let us see an example of using the convolve () method with 3 different modes and its demonstration in the below section. Let us see the convolution of two one-dimensional arrays using all 3 modes (full, same, valid).

What is the use of convolution in Python?

In mathematical terms, convolution is a mathematical operator generally used in signal processing. An array in numpy acts as the signal. The np.convolve () is a built-in numpy library method used to return discrete, linear convolution of two one-dimensional vectors.


2 Answers

Convolution is a mathematical operator primarily used in signal processing. Numpy simply uses this signal processing nomenclature to define it, hence the "signal" references. An array in numpy is a signal. The convolution of two signals is defined as the integral of the first signal, reversed, sweeping over ("convolved onto") the second signal and multiplied (with the scalar product) at each position of overlapping vectors. The first signal is often called the kernel, especially when it is a 2-D matrix in image processing or neural networks, and the reversal becomes a mirroring in 2-D (NOT transpose). It can more clearly be understood using the animations on wikipedia.

Convolutions have multiple definitions depending on the context. Some start the convolution when the overlap begins while others start when the overlap is only partial. In the case of numpy's "valid" mode, the overlap is specified to be always complete. It is called "valid" since every value given in the result is done without data extrapolation.

For instance, if your array X have a length of 2 and your array Y have a length of 4, the convolution of X onto Y in "valid" mode will give you an array of length 3.

First step, for X = [4 3] and Y = [1 1 5 5]:

[3 4]                   (X is reversed from [4 3] to [3 4], see note)
[1 1 5 5]
= 3 * 1 + 4 * 1 = 7

Note: If X was not reversed, the operation would be called a cross-correlation instead of a convolution.

Second Step:

  [3 4]
[1 1 5 5]
= 3 * 1 + 4 * 5 = 23

Third step:

    [3 4]
[1 1 5 5]
= 3 * 5 + 4 * 5 = 35

The result of the convolution for mode "valid" would then be [7 23 35].

If the overlap is be specified as one single data point (as the case in mode "full"), the result would have given you an array of length 5. The first step being:

[3 4]
  [1 1 5 5]
= 3 * undefined (extrapolated as 0) + 4 * 1 = 4

And so on. More extrapolation modes exist.

like image 187
Soravux Avatar answered Oct 19 '22 12:10

Soravux


It is notable also that the kernel is "centered" in the sense that indices for the kernel are taken with respect to the centre element of the array. In other words, for arrays with index starting at 0 (as in python), the function B = np.convolve (A, K) computes

B[k] = \sum_i A[i]   K[k - i + m]

where m = (len(K) - 1)//2 (integer division). This is an integer, also when len(K) is even.

The summation is nominally over all values of i from -∞ to ∞, where values of A out of range are assumed equal to zero. The same is true for values of the kernel. For np.convolution2D, you have to option of using the mode, boundary and fillvalue options to specify how values of A out of range are treated.

Thus, for example, you get different answers for np.convolve(A, K) if K = np.array([1, 2, 3]) or K = np.array([1, 2, 3, 0, 0])

like image 39
Richard Hartley Avatar answered Oct 19 '22 11:10

Richard Hartley