So I'm trying to find all sub-lists of a list and here is what I have now. I'm new to Python and I don't understand why " Q3_ans=set(ans)" raises an error. I've tried to convert a list to set before and it works.
def f2(seq):
'''
This is the base case of the recursion from function all_sublists
'''
assert len(seq)==2
assert isinstance(x,list)
a,b=seq
return [[a],[b],[a,b]]
def all_sublists(x):
'''
This function will generate all of the sublists of a list, not including the empty one, using recursion
'''
assert isinstance(x,list)
ans=[]
for i in range(0,len(x)-1):
for j in range(1,len(x)):
temp=[x[i],x[j]]
temp=[f2(temp)]
ans.extend(temp)
Q3_ans=set(ans)
return Q3_ans
Here is the error when I run my code y=[1,2,3,4,5]
all_sublists(y)
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-108-f8b1bb0a7001> in <module>
----> 1 all_sublists(y)
<ipython-input-106-84f4f752e98e> in all_sublists(x)
10 temp=[f2(temp)]
11 ans.extend(temp)
---> 12 Q3_ans=set(ans)
13 return Q3_ans
TypeError: unhashable type: 'list'
This error occurs when trying to hash a list, which is an unhashable object. For example, using a list as a key in a Python dictionary will cause this error since dictionaries only accept hashable data types as a key. The standard way to solve this issue is to cast a list to a tuple, which is a hashable data type.
The Python "TypeError: unhashable type: 'dict'" occurs when we use a dictionary as a key in another dictionary or as an element in a set . To solve the error, use a frozenset instead, or convert the dictionary into a JSON string before using it as a key.
TypeError: unhashable type: 'list' usually means that you are trying to use a list as an hash argument. This means that when you try to hash an unhashable object it will result an error. For ex. when you use a list as a key in the dictionary , this cannot be done because lists can't be hashed.
Adding a NumPy Array to a Set Therefore, the code above should return an error: We can solve this by adding each array element instead of the array object into the set. This should add all the elements of the array to the set.
Here's the essence of the problem:
>>> set([[["a"],["b"],["a","b"]]])
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: unhashable type: 'list'
So, what does that mean?
set([iterable])
Return a new set ... object whose elements are taken from iterable. The elements of a set must be hashable.
hashable
An object is hashable if it has a hash value which never changes during its lifetime (it needs a
__hash__()
method), and can be compared to other objects (it needs an__eq__()
method). Hashable objects which compare equal must have the same hash value.Hashability makes an object usable as a dictionary key and a set member, because these data structures use the hash value internally.
All of Python’s immutable built-in objects are hashable; mutable containers (such as lists or dictionaries) are not.
The keywords here are mutable
Mutable objects can change their value but keep their id().
and immutable
An object with a fixed value. Immutable objects include numbers, strings and tuples. Such an object cannot be altered. A new object has to be created if a different value has to be stored. They play an important role in places where a constant hash value is needed, for example as a key in a dictionary.
So, you can't use a list
as set
element. A tuple
would work:
>>> set([(("a"),("b"),("a","b"))])
{('a', 'b', ('a', 'b'))}
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