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UML association multiplicity

I have a question about association multiplicity. I understand it, but for example if I would have:

 ---------            ---------
|         |1      *  |         |
|CLASS    |----------| STUDENT |
|         |          |         |
 ---------            ---------

does that mean that at ANY point during system existence there must be at least 1 student assigned to the class, or those multiplicities should be true, if the system is operating normally?

I am asking this question, because I was wondering about the moment of creation for an object. First we create an empty class, then populate it with students. For some time the class is empty, but only during the creation and populating it will have has at least one student. If I changed 1 to 0..1 it would suggest there can be empty class. This isn't false (at the moment of populating) but later I don't want to permit classes with no students.

EDIT: changed 0..* to 0..1, it should be like it is now, sorry for confusion.

like image 553
Andna Avatar asked Mar 10 '12 22:03

Andna


2 Answers

dose that mean that at ANY point during system existence there must be at least 1 student assigned to the class, or those multiplicities should be true, if the system is operating normally.

That's a good question. It means that, when the system is in a stable state, every Student MUST be associated with exactly one Class. That in turn raises another question: what constitutes a 'stable state'? UML in general doesn't formalise this. Intuitively, it means when there's no activity in progress that is actively changing state. Some profiles of UML put more rigour around this. For example, Executable UML says that the system can violate the cardinality constraints while the action of a state is executing. However when the state action completes it must leave the system in valid state, i.e. where all cardinality constraints are satisfied.

Databases provide a good analogy here. DB constraints (such as not null & foreign keys) must hold true when the system is stable. During the execution of a transaction the constraints may be temporarily violated. However, when the transaction completes, it must leave the db in a valid state.

So for your example as shown:

  • It is valid for a Class to exist with no Students when the system is stable (* says 0 or more - so Class need not have any Students)
  • It is not valid for a Student to exist without being assigned to a Class when the system is stable ('1' means exactly one). So whatever 'transaction' creates the Student must also associate the Student with a Class.

hth.

like image 160
sfinnie Avatar answered Sep 23 '22 17:09

sfinnie


dose that mean that at ANY point during system existence there must be at least 1 student assigned to the class

It means there is exactly one class assigned to multiple students.

Each end of the association has an upper multiplicity boundary and a lower multiplicity boundary, but most UML editors will only show one value if the upper and lower boundaries are the same. If you want to allow (zero or one) to many, you can write it like this:

0..1      *  
-----------

What you really probably want here is a many-to-many relationship... students can be in many classes, and classes can contain many students.

like image 41
Dagg Nabbit Avatar answered Sep 20 '22 17:09

Dagg Nabbit