UITableView cell creation on Swift

Question

I am trying to create UITableViewCell with swift, on my delegate method cellForRowAtIndexPath,

the code is simple as in Objective-c, just trying to morph the language to swift.

I am getting error on this line

var cell:UITableViewCell = tableView.dequeueReusableCellWithIdentifier(cellIdentifier) as UITableViewCell

    if(cell == nil)
    {
        let cell: UITableViewCell = UITableViewCell(style: UITableViewCellStyle.Subtitle,reuseIdentifier:cellIdentifier)
    }

error is UITableViewCell is not convertible to "MirrorDisposition"

I have looked up examples, the code was like this

if !cell
{let cell: UITableViewCell = UITableViewCell(style: UITableViewCellStyle.Subtitle,reuseIdentifier:cellIdentifier)
}

but it also gives an error.

What am i doing wrong?

Answer 1

As of the latest beta (beta 6) non optional types cannot be compared with nil.

Therefore you must declare your cell Var as an Optional.

Something like this will work correctly (off the top of my head - I don't have Xcode in front of me):

//declare a tableViewCell as an implicitly unwrapped optional...
var cell:UITableViewCell! = tableView.dequeueReusableCellWithIdentifier(cellIdentifier) as? UITableViewCell

//you CAN check this against nil, if nil then create a cell (don't redeclare like you were doing...
if(cell == nil)
{
  cell = UITableViewCell(style: UITableViewCellStyle.Subtitle,reuseIdentifier:cellIdentifier)
}

Answer 2

A far better option is to use the more modern method which always returns a cell (as long as you are using a storyboard, or have registered the nib or class for the cell)

let cell = tableView.dequeueReusableCellWithIdentifier(cellIdentifier, forIndexPath: indexPath) as UITableViewCell

Since the method always returns a cell, it's not an optional, and there as no need to check for nil.