Just found a piece of my code that had one original typo in it.
$msg = "Some text";
$msg .= " some more text";
$msg .+ " yet more text!";
$msg .= " last text";
Notice the .+
that should be .=
. What surprises me is that the code ran without producing any error, warning or notice and the output was:
Some text some more text last text
I was wondering why it did that. I know full well what .=
and +=
are but how is .+
interpreted especially since there is no equal sign.
Syntax Error – This error is caused by an error in the PHP structure when a character is missing or added that shouldn't be there. Unexpected – This means the code is missing a character and PHP reaches the end of the file without finding what it's looking for.
A parse error: syntax error, unexpected appears when the PHP interpreter detects a missing element. Most of the time, it is caused by a missing curly bracket “}”. To solve this, it will require you to scan the entire file to find the source of the error.
If the PHP code contains a syntax error, the PHP parser cannot interpret the code and stops working. For example, a syntax error can be a forgotten quotation mark, a missing semicolon at the end of a line, missing parenthesis, or extra characters.
There's no .+
operator, so that is .
followed by +
.
You're building an expression that consists of $msg
concatenated with the result of applying unary +
to " yet more text!"
(which is 0
due to the cast to integer) ... and then discarding the whole thing because you're not doing anything with the result.
$msg .+ " yet more text!";
$msg . +" yet more text!"; // 1. PHP doesn't care about the spacing
$msg . 0; // 2. Conversion to int from unary `+`
$msg . "0"; // 3. Coersion to string for concatenation
// 4. Nothing done with value
It's perfectly valid; it just doesn't do anything useful.
The +
gets interpreted as a unary plus. PHP casts the string into an integer with the value 0 and concatenates it with $msg
. However you do not assign $msg
anything on that line, so $msg
won't be changed.
This works because the .
is the concatenation operator, and +
is the addition operator.
The line got interpreted like this:
$msg . (+" yet more text!");
The expression +" yet more text!"
converts the string to an int (0
in this case as when PHP converts a string to an int, it stops at the 1st non-number character). It then concated the 0
to $msg
, and ignored the result.
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