I'm using typescript for a project and need to serialize a collection to json, save it to a file and later deserialize that file into a similar collection. The collection looks something like:
elements: Array<tool>
and my tool interface looks like:
export interface tool {
name: string;
draw(context:any);
}
and a tool implementation would look like:
export class textTool implements tool {
name: string;
fontSize:number;
fontType:string;
draw(context:any){
// draws the control...
}
}
I have few implementations of tool interface: textTool, imageTool and rectangleTool. The problem I need to solve is that when I deserialize the file content into a collection of tool I get just a regular object and not an instance of textTool for example.
I'm using JSON.stringify(elements)
to create a json and JSON.parse(jsonText)
to deserialize.
I understand that the parser has no way to know which type it should create an instance of given the json text has no information about it. I thought of adding a field or something to identify which class instance I need and manually 'new' that class. Any options where I don't need to manually parse the json to collection of tool (with proper types)?
As you said you can add a field type
, create a mapping between type-string to implementation-class and then conversion code will be pretty straight forward:
export interface tool {
type: string;
name: string;
draw(context:any): void;
}
class textTool implements tool {
type:string = 'textTool';
name:string;
fontSize:number;
fontType:string;
draw(context:any):void {
}
}
const typeMapping:any = {
'textTool' : textTool
//all other types
};
let json = '[{"type":"textTool", "name": "someName", "fontSize": 11}]';
let elements: Array<tool> = JSON.parse(json).map((i:any) => {
let target:any = new typeMapping[i.type];
for (const key in i) {
target[key] = i[key];
}
return target;
});
* Cloning code is very simplistic, but it is good enough for plain objects.
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