sTypeName = ... //do some string stuff here to get the name of the type
/*
The Assembly.CreateInstance function returns a type
of System.object. I want to type cast it to
the type whose name is sTypeName.
assembly.CreateInstance(sTypeName)
So, in effect I want to do something like:
*/
assembly.CreateInstance(sTypeName) as Type.GetType(sTypeName);
How do I do that? And, what do I take on the left side of the assignment expression, assuming this is C# 2.0. I don't have the var keyword.
Usually you let all classes, you want to instantiate this dynamically, implement a common interface, lets say IMyInterface
. You can create an instance from the classname string like this:
Assembly asm = Assembly.GetExecutingAssembly();
string classname = "MyNamespace.MyClass";
Type classtype = asm.GetType(classname);
// Constructor without parameters
IMyInterface instance = (IMyInterface)Activator.CreateInstance(classtype);
// With parameters (eg. first: string, second: int):
IMyInterface instance = (IMyInterface)Activator.CreateInstance(classtype,
new object[]{
(object)"param1",
(object)5
});
Even if you dont have a common interface, but know the name of the method (as string) you can invoke your methods like this (very similar for properties, event and so on):
object instance = Activator.CreateInstance(classtype);
int result = (int)classtype.GetMethod("TwoTimes").Invoke(instance,
new object[] { 15 });
// result = 30
The example class:
namespace MyNamespace
{
public class MyClass
{
public MyClass(string s, int i) { }
public int TwoTimes(int i)
{
return i * 2;
}
}
}
Unfortunately there's no way in .NET to do what you want.
Possible partial solutions are:
If you know the type at compile-time (unlikely, since you're creating it at run-time from a string) then simply cast to that type:
YourType t = (YourType)Activator.CreateInstance(sTypeName);
If you know that all the possible types will implement a specific, common interface then you can cast to that interface instead:
IYourInterface i = (IYourInterface)Activator.CreateInstance(sTypeName);
If you can't do either of the above then, unfortunately, you're stuck with object
and reflection.
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