Using GCC 4.2. I have this metatemplate for conditional type:
template <bool condition, typename Then, typename Else>
struct IF
{
typedef Then RET;
};
template <class Then, class Else>
struct IF<false, Then, Else>
{
typedef Else RET;
};
and when I use it like this:
template <typename T>
class Param
{
IF< sizeof(int)<sizeof(long), long, int>::RET i;
};
it works, but when I use it like this (trying to use template parameters):
template <typename T>
class Param
{
IF< sizeof(int)<sizeof(long), T&, T* >::RET mParam;
};
I am getting this error code:
error: type 'IF<false, T&, T*>' is not derived from type 'Param<T>'
Why is it happening? How to solve it? Thanks in advance!
In the second case, what RET
is, depends on the template type T
. The compiler needs to be assured that it is going to be a type in all possible instantiations (and not perhaps a static member of some instantiation of IF). You do so with the typename
keyword.
template <typename T>
class Param
{
typename IF< sizeof(int)<sizeof(long), T&, T* >::RET mParam;
};
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